The correct answer is D
Explanation:
Wave frequency is mainly determined by the number of waves that pass through a specific point. In a diagram, this can be found by analyzing the number of crests (top of the wave) and the space between them. For example, wave B is the one with the lowest frequency because there is only one crest and this shows only one wave passing at a specific point. On the opposite, wave D is the one with the highest frequency because this shows multiple crests and this indicates the frequency is high or that many waves pass through a specific point in a short time.
Answer:
The answer is a compound.
it is a compound as it contains different elements
Explanation:
Answer:
The formation of large molecules from small repeating units is known as <u>Condensation</u> reactions.
Explanation:
Those reactions in which two molecules join together with a elimination of small neutral molecule like H₂O, CH₃OH, HCl e.t.c are known as condensation reactions.
Polymerization reactions are those reactions in which small molecules called as monomers join together to form a large molecule also known as polymers. These reactions are done via different mechanisms among which one is the condensation reaction.
Example:
Proteins (polymer) are made up of amino acids (monomers) through condensation reaction as,
n H₂N-RH-COOH → H₂N-[-RH]n-COOH + n H₂O
In above equation "n" represent large number, H₂N-RH-COOH represent amino acid (monomer) and H₂N-[-RH]n-COOH represent protein (polymer). While, the H₂O eliminated is the small neutral molecule.
Because it's oil and oil always sits on top of water
Answer:
Compound A: Propylbenzene
Compound B: Cumene
Explanation:
On this case, we have two clues:
<u>1) The mass spectrometry info</u>
<u>2) The formation of benzoic acid</u>
If we have the formation of benzoic acid with a strong oxidant (
). It means that we have an <u>alky group bonded to benzene</u>. Therefore we have to <u>add three carbons to a benzene</u> ring in order to obtain the mass of the compound (120).
The next question is <u>how these three additional carbons are bonded</u> to the benzene. For this, we have to check the mass info. For compound A we have a <u>fragmentation moeity on 91</u> therefore we have a <u>loss of an ethyl group</u>. Therefore compound A have a <u>linear structure</u> for the aditional three carbons.
For compound B we have a <u>fragmentation moeity on 105</u> this means a loss of 15 units of mass therefore we <u>loss a methyl grou</u>p. This indicates that we have a <u>non linear structure</u> fo the three additional carbons.
See figures 1 and 2.
I hope it helps!