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tigry1 [53]
3 years ago
6

I NEED HELP PLEASE ASAP!! BRAINLIEST :)

Chemistry
1 answer:
SVEN [57.7K]3 years ago
3 0

Answer:

Higher

Explanation:

When an object sublimates, it goes straight from the solid to the gas phase. Since this involves heating up, the object's molecules move faster, which therefore gives it higher kinetic energy. Hope this helps!

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How many significant figures is in 1234
DENIUS [597]

Answer:

4 significant figures.

Explanation:

The given measurement have four significant figures 1234.

All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.

Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.

Zero between the non zero digits are consider significant like 104 consist of three significant figures.

The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.

8 0
3 years ago
Which process takes place when large rocks crumble due to oxidation?
jok3333 [9.3K]
Abrasion is the answer
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3 years ago
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The activation energy for the reaction NO2 (g )+ CO (g) ⟶ NO (g) + CO2 (g) is Ea = 218 kJ/mol and the change in enthalpy for the
madreJ [45]

Answer:

470\frac{KJ}{mol}

Explanation:

The activation energy represents the energy barrier that reagents must pass to transform into products (or products to transform into reagents in a reverse reaction)

For any reaction, the change in enthalpy is related to the activation energy by the equation

\Delta H =E_{a\ direct}-E_{a\ reverse}

So, the activation energy for the reverse reaction is

E_{a\ reverse}=E_{a\ direct}-\Delta H =218 \frac{KJ}{mol} - (-252)\frac{KJ}{mol}=470\frac{KJ}{mol}

4 0
3 years ago
The equation 2Na + Cl2 ---&gt; 2NaCl, 2 NaCl is a:<br><br>​
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\huge\mathrm {Answer࿐}

\mathrm{2Na + Cl_2  \rightarrow2NaCl}

In the above equation, the product formed is :

\large\boxed{ \mathrm{NaCl}}

_____________________________

\mathrm{ \#TeeNForeveR}

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3 years ago
You have a 28.2-g sample of a metal heated to 95.2°c. you drop it in a calorimeter with 100. g of water at 25.1°c. the final tem
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The heat lost by the metal should be equal to the heat gained by the water. We know that the heat capacity of water is simply 4.186 J / g °C. Therefore:

100 g * 4.186 J / g °C * (31°C – 25.1°C) = 28.2 g * Cp * (95.2°C - 31°C)

<span>Cp = 1.36 J / g °C</span>

4 0
4 years ago
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