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Nutka1998 [239]
3 years ago
10

A mammoth skeleton has a carbon-14 decay rate of 0.49 disintegrations per minute per gram of carbon (0.49 dis/min⋅gC ). You may

want to reference (Pages 950 - 955) section 20.6 while completing this problem. Part A When did the mammoth live? (Assume that living organisms have a carbon-14 decay rate of 15.3 dis/min⋅gC and that carbon-14 has a half-life of 5715 yr.)
Chemistry
1 answer:
jenyasd209 [6]3 years ago
7 0

Answer:

t = 28379.5 years

Explanation:

<u>To find when did the mammoth live, we need to use the exponential decay equation</u>:          

\frac{N_{t}}{N_{0}}= \frac{1}{2}^ \frac{t}{t_{1/2}}  

<em />

<em>where, </em><em>N(t)/N(0): ratio decay rate, t: time to find, t(1/2): half-life</em><em> </em>

   

\frac{0.49}{15.3} = \frac{1}{2}^ \frac{t}{5715}  

Log(0.032) = \frac{t}{5715} \cdot Log(0.5)

t= \frac {5715 \cdot Log(0.032)}{Log(0.5)}  

t= 28379.5 years

Have a nice day!                

     

     

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<h3>Learn more about:</h3>
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Level: High school  

Subject: Chemistry  

Topic: structure and bonding  

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