The patient needs 1000 ml of 5% (w/v) glucose solution
i.e 1000 ml x 5 g/ 100 ml
where the stock solution is 55% (w/v) = 55 g / 100 ml
So, 1000 ml x 5 g / 100 ml = V (ml) x 55 g / 100 ml
V = 1000 x (5 / 100) / (55 / 100) = 5000 / 55 = 90.9 ml
∴ the patient needs 90.9 ml of 55% (w/v) glucose solution
Answer:
Hydrogen H₂ will be the limiting reagent.
The excess reactant that will be left after the reaction is 3.45 moles.
4.3 moles of water can be produced.
Explanation:
The balanced reation is:
2 H₂ + O₂ → 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- H₂: 2 moles
- O₂: 1 mole
- H₂O: 2 moles
To determine the limiting reagent, you can use a simple rule of three as follows: if by stoichiometry 1 mole of O₂ reacts with 2 moles of H₂, how much moles of H₂ will be needed if 5.6 moles of O₂ react?
moles of H₂= 11.2 moles
But 11.2 moles of H₂ are not available, 4.3 moles are available. Since you have less moles than you need to react with 5.6 moles of O₂, <u><em>hydrogen H₂ will be the limiting reagent</em></u> and oxygen O₂ will be the excess reagent.
Then you can apply the following rules of three:
- If by reaction stoichiometry 2 moles of H₂ react with 1 mole of O₂, 4.3 moles of H₂ will react with how many moles of O₂?
moles of O₂= 2.15 moles
The excess reactant that will be left after the reaction can be calculated as:
5.6 moles - 2.15 moles= 3.45 moles
<u><em>The excess reactant that will be left after the reaction is 3.45 moles.</em></u>
- If by reaction stoichiometry 2 moles of H₂ produce 2 moles of H₂O, 4.3 moles of H₂ produce how many moles of H₂O?
moles of H₂O= 4.3 moles
<u><em>4.3 moles of water can be produced.</em></u>
Answer:
P₂ = 3.86 atm .
Explanation:
We assume that during this change , the temperature of the gas remains constant .
So the gas will obey Boyle's law .
P₁ V₁ = P₂V₂
5.08 x 7.56 = P₂ x 9.94
P₂ = 3.86 atm .
Answer:
"0.053457 M" of sulfuric acid.
Explanation:
The given values are:
= 10 mL solution
= 12.20 mL
= 22.20 mL
then,
M 0.103 M of NaOH,
= experiment will not be affected
= 10.38 mL
Now,
⇒ mol of NAOH = MV
=
=
Whether Sulfuric acid, then
⇒
⇒
⇒
Before any dilution:
⇒
(Sulfuric acid)
Answer:
a) False
b) False
c) True
Explanation:
a) Most sulfur oxides formed during combustion come from sulfur in the air: The sulfur burns in presence of oxygen to produce sulfur oxides, the source of sulfur is anthropogenic activities (Human activities).
So the given statement is false.
b) A flue gas scrubber removes SO2 pollution in a coal-fired power plant by using lime to convert the SO2 into alcohols:
False
The lime reacts with sulfur dioxide to give carbon dioxide and calcium sulfite.
c) True
c)