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goldfiish [28.3K]
3 years ago
12

Which statements are true about Figure I and Figure II below? (Check all that apply)

Chemistry
1 answer:
Scilla [17]3 years ago
5 0

Both figures are mixtures,

Figure II is a heterogenous mixture

Figure I is a homogenous mixture

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Which of the following is an example of a model?
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2 years ago
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A solution of pH 5 is diluted 100 times. Find the pH of the resulting solution.
liq [111]
First, we calculate of the concentration of the H+ ions in the solution from the pH given. Then, calculate the new concentration after dilution. Calculation are as follows:

pH = -log[H+]
5 = -log[H+]
[H+] = 1 x 10^-5 M

M1V1 = M2V2
<span>1 x 10^-5 M (V1) = M2(100V1)
</span>M2 = 1 x 10^-7

pH =  -log[<span>1 x 10^-7</span>]
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How many grams of C6H12O6 are needed to be dissolved in water to make 100. grams of a 250. ppm solution?
Vesna [10]

Answer:

0.025 g C6H12O6

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4 0
3 years ago
Please help I will mark you brainiest
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8 0
3 years ago
A 7.00-mL portion of 8.00 M stock solution is to be diluted to 0.800 M. What will be the final volume after dilution? Enter your
amm1812

Explanation:

The number of moles of solute present in liter of solution is defined as molarity.

Mathematically,         Molarity = \frac{\text{no. of moles}}{\text{Volume in liter}}

Also, when number of moles are equal in a solution then the formula will be as follows.

                     M_{1} \times V_{1} = M_{2} \times V_{2}

It is given that M_{1} is 8.00 M, V_{1} is 7.00 mL, and M_{2} is 0.80 M.

Hence, calculate the value of V_{2} using above formula as follows.

                    M_{1} \times V_{1} = M_{2} \times V_{2}

                 8.00 M \times 7.00 mL = 0.80 M \times V_{2}

                      V_{2} = \frac{56 M. mL}{0.80 M}

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Thus, we can conclude that the volume after dilution is 70 ml.

7 0
2 years ago
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