The formula for the fundamental frequency for an open tube at one end is : F = nV/4L the integer n = 3 which describe the frequency 450 hertz and length of tube L = 0.6m approximately
<h3>What is frequency?</h3>
Frequency of the object is defined as the number of cycles attend in a second .
Given that a tube is open only at one end. And a certain harmonic produced by the tube has a frequency of 450 Hz. The next higher harmonic has a frequency of 750 Hz. The formula for the fundamental frequency for an open tube at one end is :

That is, 1st harmonic

2nd harmonic =

3rd harmonic =

The general formula can therefore be 
For the first harmonic in the question,

make 4L the subject of the formula

The next higher harmonic will be

make 4L the subject of the formula

Equate the two 4L

cross multiply


collect the likes term



n = 3
Given that the speed of sound in air is 343 m/s, The length of the tube can be calculate by using the same formula.



4L = 2.28

L = 0.57 m
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