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Radda [10]
2 years ago
7

A block of iron at 33.0°C has mass 2.30 kg. If 3.50×104 J of heat are transferred to the block, what is its resulting temperatur

e?
Physics
1 answer:
spayn [35]2 years ago
3 0

Answer:

66.8°C

Explanation:

dQ = m*cp*dT where:

m = mass of block

cp = specific heat of iron

dT = temperature change

-------

dQ = 3.5 10^4 J

cp = 0.45 Kj / Kg = 450 J / Kg

3.5 10^4 = 2.3 * 450 * dt-----dt = 35000 / 450 * 2.3 = 33.8 °

-------

Final temperature = 33 + 33.8 = 66.8 °C

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Answer: Stationary or constant velocity

Explanation:

Objects with balanced forces acting on them experience no change in motion, or no acceleration. So these objects could either be stationary at rest or have a constant velocity. These include a hanging object, a floating object, an object on a table that doesn't move, and a car moving at a constant 10 mph

4 0
2 years ago
What is CGS and SI unit of weight?​
Marta_Voda [28]

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2 years ago
A car moves 50km in the first 30 minutes and 50km in the second 30 minutes and continues in this way which motion is this ------
egoroff_w [7]

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Explanation:

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3 0
3 years ago
A student pulls a cart across the floor with a force of 45 N. If the cart travels 10 m, how much work does the cart do on the st
bixtya [17]
I'm assuming we're applying the standard Integral form of the calculation of work. The solution is provided in the image.  

6 0
3 years ago
An air compressor compresses 6 L of air at 120 kPa and 22°C to 1000 kPa and 400°C. Determine the flow work, in kJ/kg, required b
Mariana [72]

Answer:

The work flow required by the compressor = 100.67Kj/kg

Explanation:

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The work flow can be determined using the equation:

M1h1 + W = Mh2

U1 + P1alph1 + ◇U + Workflow = U2 + P2alpha2

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Workflow = 100.672Kj/kg

6 0
3 years ago
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