Answer:
theoretical probability
Step-by-step explanation:
This is theoretical probability. The 7 pieces of paper each bear one number from {1, 2, ... , 6, 7}. There is only one piece of paper marked 7. So the probability of drawing a 2 is 1/7.
Answer: 1: B
Step-by-step explanation:
Answer:
48
Step-by-step explanation:
First, in this problem, you would assume that there are five numbers to multiply since Dwayne played 5 games.
In the first blank, he could choose any move, and there are three, rock, paper, and scissors. In the first blank, you would put 3. Then, since you already picked one, you can't repeat it, so you would end up with 2 for the second blank. Continuing with the next blanks, the third, fourth, and fifth spaces would be 2 choices because you cannot have the one choice you chose previously. In the end, the blanks would look somewhat like this:
3 2 2 2 2
And you would multiply all the numbers.
3 x 2 x 2 x 2 x 2
= 6 x 8
= 48
Answer:
Therefore
15.
![25c^{2}-9](https://tex.z-dn.net/?f=25c%5E%7B2%7D-9)
16.
![(y+8)(y+1)](https://tex.z-dn.net/?f=%28y%2B8%29%28y%2B1%29)
17.
![(x-3y)(x-7y)](https://tex.z-dn.net/?f=%28x-3y%29%28x-7y%29)
Step-by-step explanation:
15.
![(5c^{2} +3)(5c^{2}-3)](https://tex.z-dn.net/?f=%285c%5E%7B2%7D%20%2B3%29%285c%5E%7B2%7D-3%29)
Using the Identity (a + b)(a - b) = (a² - b²) we get
Consider here a = 5c and b = 3 then we will have
.....as required
16.
![y^{2}+9y+8](https://tex.z-dn.net/?f=y%5E%7B2%7D%2B9y%2B8)
Here Factorize 8 such that sum up to be 9
∴ 8 × 1 = 8 and 8 + 1 =9
... as required
17.
![x^{2}-10xy+21y^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D-10xy%2B21y%5E%7B2%7D)
Here Factorize 21 such that sum up to be -10
∴ -3 × -7 = + 21 and -3 - 7 = - 10
........as required
Therefore
15.
![25c^{2}-9](https://tex.z-dn.net/?f=25c%5E%7B2%7D-9)
16.
![(y+8)(y+1)](https://tex.z-dn.net/?f=%28y%2B8%29%28y%2B1%29)
17.
![(x-3y)(x-7y)](https://tex.z-dn.net/?f=%28x-3y%29%28x-7y%29)