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2 years ago

Needs help with numbers 14,18,19,20

Mathematics

2 answers:

mixas84 [53]2 years ago

5 0

14 would be 300
18 would be 700 and 500
19 would be 752 and u would put 7,5,2 and round to 800
20 would be 4

Elis [28]2 years ago

3 0

All u doing is couting numbers and add on to what u have i show you 14,18,19,20,

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3 years ago

The cone had a radius of 4.5 inches and a height of 6 inches. What is the volume of this cone?

pochemuha

Answer:

125.8983

Step-by-step explanation:

Use the formula for volume of a cone: v= (1/3)(3.14)(radius squared)(height) so v = (1/3)(3.14)(20.25)(6) = 125.8983

4 0

2 years ago

Alisa hopes to play beach volleyball in the olympics someday. She has convinced her parents to allow her to set up a beach volle

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6 0

3 years ago

A rectangle has a height of 2x^4 with a width of x^2+8x+15. Express the area of the rectangle.

Amiraneli [1.4K]

Hi there!

We know that the formula for the area of a rectangle is height * width. Thus, we can multiply these two expressions together:

$2x^4\cdot (x^2+8x+15)\\$

Now, we know through the distributive property that we can distribute the $2x^4\\$ to everything in the parenthesis. Once this is done, we get:

$2x^4 \cdot x^2+2x^4\cdot8x+2x^4\cdot15$

Now, we know through the power rule that when two exponents are multiplied together with the same base, the exponent can be added together $(x^a \cdot x^b = x^{a+b})$ . This then would make our equation:

$2x^{4+2}+16x^{4+1}+30x^4\\$

Giving us for our final answer:

$2x^{6}+16x^{5}+30x^4\\$

Hope this helps!

8 0

2 years ago

Solve for this trig identity step by step.

stepladder [879]

Using trigonometric identities, and equality is reached, hence the equality is proved.

<h3>Which trigonometric identity are used to solve this question?</h3>

These three identities are used:

$\sin^2{x} + \cos^2{x} = 1 \rightarrow \cos^2{x} = 1 - \sin^2{x}$ .

$\sec^2{x} = 1 + \tan^2{x}$ .

$\sec^2{x} = \frac{1}{\cos^2{x}}$

Hence:

$\sec^4{x} = \frac{1 + \tan^2{x}}{1 - \sin^2{x}}$

$\sec^4{x} = \frac{\sec^2{x}}{\cos^2{x}}$

$\sec^4{x} = \sec^2{x} \times \sec^2{x}$

$\sec^4{x} = \sec^4{x}$

Equality is reached, hence the equality is proved.

More can be learned about trigonometric identities at brainly.com/question/24496175

#SPJ1

4 0

1 year ago