Answer:
2917.4 m/s
Explanation:
From the question given above, the following data were:
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
Radius (r) of the Moon = 1737 Km
Escape velocity (v) =?
Next, we shall determine the gravitational acceleration of the Moon. This can be obtained as follow:
Gravitational acceleration of the earth = 9.8 m/s²
Gravitational acceleration of the Moon (g) = 0.25 times the gravitational acceleration of the earth
= 0.25 × 9.8 = 2.45 m/s²
Next, we shall convert 1737 Km to metres (m). This can be obtained as follow:
1 Km = 1000 m
Therefore,
1737 Km = 1737 Km × 1000 m / 1 Km
1737 Km = 1737000 m
Thus, 1737 Km is equivalent to 1737000 m
Finally, we shall determine the escape velocity of the rocket as shown below:
Gravitational acceleration of the Moon (g) = 2.45 m/s²
Radius (r) of the moon = 1737000 m
Escape velocity (v) =?
v = √2gr
v = √(2 × 2.45 × 1737000)
v = √8511300
v = 2917.4 m/s
Thus, the escape velocity is 2917.4 m/s
Answer:
20,000, though, I'm not completely sure.
Explanation:
"Sound is generated along the length of the lightning channel as the atmosphere is heated by the electrical discharge to the order of 20,000 degrees C (3 times the temperature of the surface of the sun)."
Answer:
See below
Explanation:
KE = 1/2 m v^2 = 1/2 *6 * 32.5^2 = 3168.75 j
PE = mgh = KE at end = 3168.75 j
ME = 3168.75 j
ME is KE + PE at any point
before it falls it has no KE before it hits it has no PE
so ME = 3168.75 j
Answer:
The force exerted is 6189.4 N
Solution:
As per the question:
Area of the book, A =
Mass of the book, m = 3 kg
Pressure of the book, P =
Now,
Pressure, P =
Force, F = PA =
Force on mass of 3 kg, F' = mg =
Now, the force at the bottom is given by:
F'' = F + F' = 6160 + 29.4 = 6189.4 N