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zubka84 [21]
4 years ago
10

A car traveling at 27.4 m/s hits a bridge abutment. A passenger in the car, who has a mass of 65.0 kg, moves forward a distance

of 56.0 cm while being brought to rest by an inflated air bag. Assuming that the force that stops the passenger is constant, what is the magnitude F of this force?
Physics
1 answer:
Minchanka [31]4 years ago
6 0

Answer:

F=43570.9N

Explanation:

We can calculate the acceleration experimented by the passenger using the formula v_f^2=v_i^2+2ad, taking the initial direction of movement as the positive direction and considering it comes to a rest:

a=\frac{v_f^2-v_i^2}{2d}=\frac{-v_i^2}{2d}

Then we use Newton's 2nd Law to calculate the force the passenger of mass m experimented to have this acceleration:

F=ma=\frac{-mv_i^2}{2d}

Which for our values is:

F=\frac{-(65kg)(27.4m/s)^2}{2(0.56m)}=43570.9N

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The laboratory exercise for this chapter addresses kinematic motion. You have experienced these motions in everyday life. Instea
ki77a [65]

Answer:

A) vectors: veloicty, force

scalar:  speed, work

B)  t = 1.75 s,  C)   v = - 17 2 m / s

Explanation:

We answer each part separately

A) A vector magnitude has magnitude and direction instead a scalar magnitude has only magnitude

vector quantities: the speed of a car number is the magnitude and direction is where it goes

Force, the number is the magnitude and above that applies gives direction

Scalar magnitude: how quickly the number of the speedometer of the car

Temperature, work

B) I = 15 m height to the soil and get to calculate time = 0

        y = y₀ + v₀ t - ½ g t²

as the ball is loose its initial velocity is zero

       0 = 0 +0  - ½ g t²

       t = \sqrt{2y_o/g}

       t = \sqrt{2 \ 15/ 9.8}

       t = 1.75 s

C) the velocity to the reach the floor

      v = vo - g t

      v = 0 - g t

      v = - 9.8 1.74

       v = - 17 2 m / s

The negative signt iindicates that the speed goes down

5 0
3 years ago
An input force is a Push or pull that ________________________ to the machine
Jlenok [28]

Answer:

is applied to

Explanation:

An input force is push or pull that is applied to the machine and causes work to be done on it.

Input force for every machine should be lesser than the output force. The output force is the resulting force which produces work.

The force produced by any machine is a function of the input force and the design of the machine.

Any force applied to a machine is the input force.

8 0
4 years ago
(a) Determine the specific volume of nitrogen gas at 8.5 MPa and 139 K based on the generalized compressibility chart (Fig. A-15
Vikentia [17]

Answer:v=0.0485m^3/kg

Explanation:

PV=MRT

PV/M=RT

Pv=RT

P=8.5mpa= 850Kpa

T= 139K

v= RT/P

0.2968*139/850

v=0.0485m3/kg

Error

0.0485-0.002002/0.0485*100%

95%

4 0
3 years ago
How much work is being done if a force of 75 Newtons is used to push a box a distance of 100 meters?
lukranit [14]
Work= Force x Distance
Answer: 7500 Joules
5 0
4 years ago
What charge appears on each plate of a 10.0 μF parallel plate capacitor, when it is charged to 110 V?
elena-14-01-66 [18.8K]

Answer:

charge, q = ± 1.1 mC

Given:

Capacitance, C = 10.0\micro F = 10.0\times 10^{- 6} F

Voltage, V = 110 V

Solution:

The charge on the capacitor plates can be calculated by using the definition of capacitance as :

q ∝ V

where

q = charge

V = potential difference or Voltage

Therefore,

q = CV

Now, charge, q :

q = 10.0\times 10^{- 6}\times 110 = 1100\micro C = 1.1 mC

Therefore, the charge on the positive plate is:

q = + 1.1 mC

the charge on the negative plate is:

q = - 1.1 mC

8 0
3 years ago
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