Answer:
Yes, if the carts are travelling into opposite directions
Explanation:
The total momentum of a two carts system is the sum of the momenta of the individual carts:
where
m1, m2 are the masses of the two carts
v1, v2 are the velocities of the two carts
In order to have a total momentum of zero, we must have
(1)
Let's remind that velocity (and so, momentum as well) is a vector quantity: this means that it has a direction, so when summing together the momenta, we must also consider the sign of the velocity, depending on its direction.
Therefore, if the two carts are moving in opposite directions, the signs of the two velocities will be opposite. For example, we can have
This means that the condition in eq.(1) can be satisfied, provided that the two carts are travelling into opposite directions.
It is velocity
just did this lesson
Answer:
3.33 ohms
Explanation:
Parallel circuit :
1/Rtotal= 1/R1 + 1/R2 + 1/R3
1/Rtotal= 1/10 + 1/10 + 1/10
1/Rtotal=3/10
Therefore it Rtotal= 10/3=3.33 ohms
Hello!
Answer:
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<u>Hope this help<3</u>
Answer:
v = 16.23 m/s²
Explanation:
In the problems that have friction force this must be included in the energy conservation equation, in these cases the friction force performs dissipative work that is equal to the decrease in mechanical energy
= -
Let's look for the initial mechanical energy
= Ke = ½ k x²
Final energy
= K + U = ½ m v² + mg y
The work of the rubbing force is
= - fr d.
Let's look for the missing terms, let's start with the amount the spring compresses, let's use Hooke's law
F = - k x
x = F / k
x = 4400/1100
x = 4 m
Let's write the equation and calculate
-Fr d = (1/2 m v² + ½ mg y) - ½ k x²
½ m v² = -fr .d + 1 / 2k x² - ½ m g y
v² = 2/m (- fr .d + 1/2 k x² - ½ m g y)
v² = 2/60 (-40 4 + ½ 1100 4² - ½ 60 9.8 2.5)
v = √(7905/ 30)
v = 16.23 m/s²