All categories

3 years ago

Al considerar 51 m la distancia entre dos puntos situados realmente a 52.06 m cual es el error absoluto y relativo.

Physics

1 answer:

Tamiku [17]3 years ago

7 0

Answer:

Absolute error = 1.06 m

Relative error = 0.02

Explanation:

When considering 51 m the distance between two points actually located at 52.06 m which is the absolute and relative error.

Given that the actual distance between the two points is 52.06 m

Considered distance = 51 m

Error = Actual value - Measured value

=52.06m - 51m

=1.06m

The value is already positive, so the absolute error is also 1.06m.

Relative error =( error)/(actual value)

=1.06/52.06=0.02

Hence the relative error is 0.02.

You might be interested in

which statement below is FALSE? A Gravity acts on any object with mass. B The closer objects are, the stronger the gravitational

GenaCL600 [577]

Answer:

Explanation:

5 0

3 years ago

What is the acceleration of a boy on a skateboard if the net force on the boy is 15 N? The total mass of the boy and the skatebo

Stels [109]

   Force = (mass) x (acceleration)

If the full 15N is pointing parallel to the ground,
then

   15 N = (58 kg) x (acceleration).

Divide each side
by 58 kg: Acceleration = 15 N / 58 kg

   = (15 kg-m/s²) / (58 kg)

   = (15/58) (kg-m/kg-s²)

   = 0.26 m/s² .

7 0

3 years ago

Read 2 more answers

if you push a small act with 7,000 N force and push a heavy truck with the same force, which one will have a greater acceleratio

inn [45]

Answer:

the small one will have greater acceleration

Explanation:

force and mass are inversely proportional. force and acceleration are directly proportional. which means greater mass have smaller acceleration and smaller mass has greater acceleration. this is due to newtons second law of motion.

6 0

2 years ago

Read 2 more answers

An iron bal of mass 20kg is rolling on a flat surface. On applying force, the velocity change from 17ms to 27m/s in 5s. Calculat

pentagon [3]

Answer:

40 N

Explanation:

We first need to calculate the acceleration of the tron ball.

Since acceleration, a = (v - u)/t where u = initial velocity of iron ball = 17m/s, v = final velocity of iron ball = 27m/s and t = time taken for the change in velocity = 5 s.

So, a = (v - u)/t

= (27 m/s - 17 m/s)/5 s

= 10 m/s ÷ 5 s

= 2 m/s²

We know force on iron ball, F = ma where m = mass of iron ball = 20 kg and a = acceleration = 2 m/s²

So, F = ma

= 20 kg × 2 m/s²

= 40 kgm/s²

= 40 N

So, the magnitude of the force on the iron ball is 40 N.

4 0

2 years ago

Water drips from the nozzle of a shower onto the floor 200 cm below. The drops fall at regular (equal) intervals of time, the fi

Delicious77 [7]

Answer:

(A) 88.92 cm

(B) 22.22 cm

Explanation:

distance (s) = 200 cm = 0.2 m

initial velocity (v) = 0 m/s

acceleration due to gravity (g) = 9.8 m/s^{2}

lets first find the time (T) it takes for the first drop to strike the floor

from s = ut + $0.5at^{2}$

200 = 0 + $0.5 x 9.8 x T^{2}$

200 = $4.9 x T^{2}$

200 / 4.9 = $T^{2}$

T = 6.4

(A) When the first drop strikes the floor, how far below the nozzle is the second drop.

we can find how far the second drop was when the first drop hits the ground from the formula s = ut + $0.5at^{2}$

where

s = distance
u = initial velocity = 0
t = time, since the drops fall at regular (equal) intervals of time, the first drop striking the floor at the instant the fourth drop begins to fall there wold be 3 time intervals and this can be seen illustrated in the attached diagram. therefore the time of the second drop = 2/3 of the time it takes the first drop to strike the ground ( $\frac{2}{3}.T$ )
a = acceleration due to gravity = 9.8 m/s^{2}

substituting all required values we have

s = 0 + ( $0.5 x 9.8 x (\frac{2}{3}T)^{2}$ )

s = 0 + ( $0.5 x 9.8 x (\frac{2}{3} x 6.4)^{2}$ )

s = 88.92 cm

(B) When the first drop strikes the floor, how far below the nozzle is the third drop.

we can find how far the third drop was when the first drop hits the ground from the formula s = ut + $0.5at^{2}$

where

s = distance
u = initial velocity = 0
t = time, since the drops fall at regular (equal) intervals of time, the first drop striking the floor at the instant the fourth drop begins to fall there wold be 3 time intervals and this can be seen illustrated in the attached diagram. therefore the time of the third drop = 1/3 of the time it takes the first drop to strike the ground ( $\frac{2}{3}.T$ )
a = acceleration due to gravity = 9.8 m/s^{2}

substituting all required values we have

s = 0 + ( $0.5 x 9.8 x (\frac{1}{3}T)^{2}$ )

s = 0 + ( $0.5 x 9.8 x (\frac{1}{3} x 6.4)^{2}$ )

s = 22.22 cm

6 0

3 years ago