Answer:
im pretty sure it should be 50.0
Answer:
The horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively.
Explanation:
Using the equation of the displacement in the x-direction, we have:
(let's recall we have a constant velocity in this direction)

Where:
- v(ix) is the initil velocity in the x direction (v(ix) = 30 m/s)
- t is the time (t = 7 s)
Now, we need to use the equation of the displacement in the y-direction to find the vertical distance. Here we have an acceleration (g)

Where:
- v(iy) is the initial velocity at the y-direction. In this case, it will be 0
- t is the time
- g is the acceleration of gravity (g=9.81 m/s²)
Then, the vertical position at 7 s is:


Therefore, the horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively. The minus sign means the <u>negative value in the y-direction.</u>
I hope it helps you!
The characteristics of the RLC circuit allow to find the result for the capacitance at a resonance of 93.5 Hz is:
- Capacitance is C = 1.8 10⁻⁶ F
A series RLC circuit reaches the maximum signal for a specific frequency, called the resonance frequency, this value depends on the impedance of the circuit.
Where Z is the impedance of the circuit, R the resistance, L the inductance, C the capacitance and w the angular velocity. The negative sign is due to the fact that the current in the capacitor and the inductor are out of phase.
In the case of resonance, the impedance term completes the circuit as a resistive system.
Indicate that the inductance L = 1.6 H and the frequency f = 93.5 Hz.
Angular velocity and frequency are related.
w = 2π f
Let's substitute.
Let's calculate.
C = 1.8 10⁻⁶ F
In conclusion with the characteristics of the RLC circuits we can find the result for the capacitance at a 93.5 Hz resonance is:
- Capacitance is C = 1.8 10⁻⁶ F
Learn more about serial RLC circuits here: brainly.com/question/15595203
Answer:
B) The car at point C has less kinetic energy than the car at point B.
Explanation:
We have two types of energy involved in this situation:
- Gravitational potential energy: this is the energy related to the heigth of the car, and it is given by
, where m is the mass of the car, g is the gravitational acceleration, and h is the heigth of the car. The potential energy is higher when the car is located higher above the ground.
- Kinetic energy: this is the energy due to the motion of the car, and it is given by
, where m is the mass of the car and v is its speed. The kinetic energy is higher when the speed of the car is higher.
- The law of conservation of energy states that the total mechanical energy of the car (sum of potential energy and kinetic energy:
) is constant). This implies that when the car is at a higher point, the kinetic energy is less (because U is larger, so K must be smaller), while when the car is at a lower point, the kinetic energy is larger.
- Based on what we have written so far, we can conclude that the correct statement is:
B) The car at point C has less kinetic energy than the car at point B.
Because the car at point C is located at a higher point than point B, so the car at point C has larger potential energy than at point B, which implies that car at point C has less kinetic energy than the car at point B.
Answer:
0.12
Explanation:
The acceleration due to gravity of a planet with mass M and radius R is given as:
g = (G*M) / R²
Where G is gravitational constant.
The mass of the planet M = 3 times the mass of earth = 3 * 5.972 * 10^24 kg
The radius of the planet R = 5 times the radius of earth = 5 * 6.371 * 10^6 m
Therefore:
g(planet) = (6.67 * 10^(-11) * 3 * 5.972 * 10^24) / (5 * 6.371 * 10^6)²
g(planet) = 1.18 m/s²
Therefore ratio of acceleration due to gravity on the surface of the planet, g(planet) to acceleration due to gravity on the surface of the planet, g(earth) is:
g(planet)/g(earth) = 1.18/9.8 = 0.12