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3 years ago

The product of voltage times amperage is known as what?

Physics

1 answer:

Usimov [2.4K]3 years ago

5 0

Answer:

Power=V*I which corresponds to the second option shown: "voltage times amperage"

Explanation:

The electric power is the work done to move a charge Q across a given difference of potential V per unit of time.

Since such electrical work is the product of the potential difference V times the charge that moves through that potential, and this work is to be calculated by the unit of time, we need to divide the product by time (t) which leads to the following final simple equation

$Power=\frac{V\,Q}{t} =V\,\frac{Q}{t} = V\, I$

You might be interested in

When clothes are run through a dryer, they often become

klio [65]

Answer:

The answer is 0.

The heat and friction of the dryer provide energy to separate the charges.

The electric force separates the charges from one another

Explanation:

I believe the simplest solution would be to use dryer sheets. Teehee :)

7 0

3 years ago

A crass host pours the remnants of several bottles of wine into a jug after a party. He then inserts a cork with a 2.00-cm diame

SSSSS [86.1K]

Answer:

The extra force exerted against the bottom is 5880 N.

Explanation:

Given that,

Diameter of the bottle= 2.00 cm

Diameter of the jug = 14.0 cm

Force = 120 N

We need to calculate the extra force exerted against the bottom

Using formula of force

$F_{2}=P\times A_{2}$

$F_{2}=\dfrac{F_{1}}{A_{1}}\times A_{2}$

$F_{2}=\dfrac{F_{1}}{\pi r^2}\times\pi r^2$

$F_{2}=\dfrac{F_{1}}{\pi\times\dfrac{d_{1}^2}{4}}\times\pi\times\dfrac{d_{2}^2}{4}$

$F_{2}=(\dfrac{d_{2}}{d_{1}})^2\times F_{1}$

Put the value into the formula

$F_{2}=(\dfrac{14.0}{2.00})^2\times120$

$F_{2}=5880\ N$

Hence, The extra force exerted against the bottom is 5880 N.

6 0

3 years ago

For an object in uniform circular motion, what can you say about the directions of the velocity, acceleration, and net force vec

tigry1 [53]

Answer: The velocity vector is perpendicular to the acceleration vector; the acceleration vector is parallel to the net force vector.

Explanation:

In a uniform circular motion, the meaning of "uniform"is the same as for an uniform straight motion, i.e., the module of the velocity vector (its speed) is constant.

Now, if the object were not describing a circular trajectory, it should move at constant speed, in a straight line, provided no external forces acted upon it.

If there is an external force acting on it, making it to follow a circular trajectory, this force doesn't change the instantaneous value of the velocity, but it changes his direction instead.

While the direction is changing, it always keep tangential to the trajectory, due to if at any moment the force disappears, the body must continue in a straight line at constant speed, following a line tangent to the circle.

It can be showed, that the acceleration vector, defined as the change in velocity over time, always aims towards the center of the circle, and is perpendicular to the velocity vector.

As the only net force acting on the object (assuming a horizontal trajectory), is the one that causes the acceleration, the acceleration vector has the same direction as the net force.

7 0

3 years ago

The spectral type of this star is listed as K5V. (V means it is a main sequence star.) Based on the table below, how does the su

notka56 [123]

It turns out that the star in question belongs to the K5V star class. Thus, the surface temperature of this must be between 5200 K and 3700 K. It has a surface temperature of 6200 K to 5200 K and is a G2V class star, commonly known as Bernard's star. In other words, the star in question has a colder surface than HIP 87937. This is further explained below.

<h3>What is surface temperature?</h3>

Generally, The temperature at a surface is referred to as the surface temperature. In particular, it may refer to the surface air temperature, which is the temperature of the air that is relatively close to the earth's surface.

In conclusion, The star in question is of the K5V type. Therefore, the temperature of the surface of this must be somewhere between 5200 and 3700 kelvin. The star with the designation HIP 87937, often known as Bernard's star, is of the G2V type. Stars of this type have a surface temperature that falls anywhere between 6200 and 5200 degrees Celsius. Therefore, it should come as no surprise that the surface temperature of the given star is lower than that of HIP 87937.