Question

A flea jumps straight up to a maximum height of 0.490 m . What is its initial velocity v0 as it leaves the ground?

Answer 1

Answer:

$\huge\boxed{\sf v_o=3.1\ m/s}$

Explanation:

Given Data:

Acceleration due to gravity = g = -9.8 m/s²

Maximum Height = h = 0.490 m

At h, $v_f$ = 0

Required:

$v_o=?$

Formula:

$2gh=v_f^2-v_o^2$

Solution:

Put the givens

$2 (-9.8) (0.490) = (0)\² - v_o^2\\\\-9.604=-v_o^2\\\\9.604=v_o^2\\\\Take \ sqrt\ on \ both \ sides\\\\\sqrt{9.604}=v_o^2\\\\3.1 \ m/s=v_o\\\\v_o=3.1\ m/s\\\\\rule[225]{225}{2}$