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ycow [4]
4 years ago
5

Whenever the alternating current frequency in a series RLC circuit is halved,

Physics
1 answer:
Colt1911 [192]4 years ago
8 0

Answer:

The correct option is

a. The inductive reactance is doubled and the capacitive reactance is halved

Explanation:

For a series RLC circuit, is a resonant circuit such that the impedance, Z, is minimum at the resonance frequency

Also we have that the capacitive reactance X_C, is given as follows;

X_c = \dfrac{1}{\omega \cdot C}

Where;

ω = Angular frequency = 2πf

Where;

f = The frequency in the circuit

\therefore X_c = \dfrac{1}{2 \cdot \pi \cdot f \cdot C}

The inductive reactance is also given as follows;

X_L = \omega \cdot L =  2 \cdot \pi \cdot f \cdot L

Therefore, when the circuit frequency doubles, the inductive reactance doubles and the capacitive reactance halves

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Answer:

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Explanation:

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8 0
3 years ago
g Design an experiment you can use to determine the mass of the metal cylinder. When you explain your experiment, be sure to men
kumpel [21]

Answer:

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graph of x vs m

Explanation:

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              F_e -W = 0

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We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.

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