Answer:
Wt= 0.73kJ, Wg=0.21kJ Wn= 0J
(B) Wf= 0.096kJ
Explanation:
See attachment below.
Answer:
1125.66956 N
Explanation:
m = Mass of stunt performer
g = Acceleration due to gravity = 9.81 m/s²
v = Velocity of the swing = 7 m/s
T = Tension
r = Radius of the swing = Length of vine = 11.5 m
From the free body diagram

The minimum tension force the vine must be able to support without breaking is 1125.66956 N
maximum speed of cheetah is

speed of gazelle is given as

Now the relative speed of Cheetah with respect to Gazelle


now the relative distance between Cheetah and Gazelle is given initially as "d"
now the time taken by Cheetah to catch the Gazelle is given as

so by rearranging the terms we can say


so above is the relation between all given variable
Answer:
6.29 m
Explanation:
The speed of a wave is equal to frequency times wavelength, so to find wavelength you'd have to divide frequency by both sides, speed(346) divided frequency(55) = 6.29 m
I'm not so sure about this let me know if I'm wrong
The vector force on the unit positive charge placed at any location in the field defines the strength of the electric field at that point. The charge used to determine field intensity (field strength) is known as the test charge. Now, a field line is defined as a line to which the previously mentioned field strength vectors are tangents at the relevant places. When we study positive charge field lines, the field strength vectors point away from the positive charge. If there is a negative charge anywhere in the vicinity, the field lines that began from the positive charge will all terminate at the negative charge if the value of the negative charge is the same as the value of the positive charge. Remember that the number of field lines originating from positive charge is proportional to the charge's value, and similarly, the number of field lines terminating at negative charge is proportionate to the charge's value. As a result, if all charges are equivalent, all lines originating from the positive charge terminate at the negative charge. If the value of the positive charge is greater than the value of the negative charge, the number of lines ending at the negative charge will be proportionally less than the number of lines beginning at the positive charge. The remaining lines that do not end at the negative charge will go to infinity. If the positive charge is less, all lines from it terminate at a negative charge, and any other reasonable number of ines terminate at a negative charge from infinity. We should also keep in mind that the number of lines that run perpendicular to the field direction across a surface of unit area is proportional to the field strength at that location. As a result, lines are dense in the strong field zone and sparse in the low intensity region.