Ask question

Ask question

All categories

bearhunter [10]

3 years ago

11

Suppose a child drives a bumper car head on into the side rail which exerts a force of 4000 N on the car for 0.200 s. What impul

se is imparted by this force to the car in kg m/s

1 answer:

Ghella [55]3 years ago

7 0

Por the impulse, use the formula:

I = F * t

Now, we know:

4000 N = 4000 kg*m/s²

Replacing we have:

I = 4000 kg*m/s² * 0,200 s

Resolving:

I = 800 kg.m/s²

The impulse is <u>800 kg.m/s²</u>

You might be interested in

A boat has a porthole window, of

jekas [21]

Answer:

F = 534.6[N]

Explanation:

We must find the pressure exerted by the water at the depth of the boat, by means of the following equation.

$P=Ro*g*h$

where:

Ro = density of sea water = 1027 [kg/m³]

g = gravity acceleration = 9.81 [m/s²]

h = wáter Depth = 6.25 [m]

Now replacing:

$P=1027*9.81*6.25\\P=62967.93[Pa]$

The net force is:

$F = P*A\\F = 62967.93*0.00849\\F = 534.6[N]$

7 0

3 years ago

Please help!! The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of

Bogdan [553]

Answer:

1.3 m/s

Explanation:

average speed = total distance/ total time

6 0

4 years ago

Hii can someone please doo this! 50 pointss.

andrey2020 [161]

Answer:

The periodic table illustrate some of the elements from Hydrogen to Calcium

8 0

3 years ago

The eyepiece of a light microscope has a magnification level of 10x. If you were looking at a paramecium under the lowest-power

tester [92]

Answer:

The total magnification will be 40x.

Explanation:

As we know if the magnification of the eyepiece of a microscope be $m_{e}$ and that of the objective be $m_{o}$ , then the total magnification is given by

$m = m_{e} \times m_{o}$

Given, $m_{e} = 10x$ and $m_{o} = 4x$

Therefore total magnification is $m = 10 \times 4 = 40x$

4 0

3 years ago

As Clinton walks he pushes his shoe against the track.

Valentin [98]

Answer:A:The track pushes back on Clinton's shoe with the same force.

Explanation:According to Newton's third law of motion, for every action force there is an equal and opposite reaction force. In this case, the action force is Clinton's shoe pushing on the track. As this happens, there is an equal and opposite reaction force in which the track pushes back on Clinton's shoe with the same force.

4 0

3 years ago