1.A law is an observation; a theory is the explanation of that observation.
2.A theory requires experimentation under various conditions. A law has no such requirements.
3.A theory may become obsolete with time. This is not the case with a law.
4.A theory can be replaced by another better theory; however, this never happens with a law.
5.A theory may be strong or weak according to the amount of evidence available. A law is a universally observable fact.
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Ur answer would’ve u have too many questions
A solid product called a may form when chemicals in two liquids react, as shown in the photograph below. ... The photo- graph below shows an example in which carbon dioxide gas<span> is </span>produced<span> by a chemical </span>reaction. Temperature Change Most chemicalreactions<span> involve a temperature. change.</span>
Answer:
Explanation:
Arrhenius defined an acid as a substance that interacts with water to produce excess hydrogen ions in aqueous solution.
A base is a substance which interacts with water to yield excess hydroxide ions, in an aqueous solution according to Arrhenius.
Bronsted-Lowry theory defined an acid as a proton donor while a base is a proton acceptor.
<h3>
Answer:</h3>
Al₂(SO₄)₃
<h3>
Explanation:</h3>
We are given percentage composition of elements in a compound;
- Aluminium is 15.77%
- Sulfur is 28.11 %
- Oxygen is 56.12%
We are required to calculate the empirical formula of the compound.
- Assuming the mass of the compound is 100 g then the masses of the elements is;
Aluminium = 15.77 g
Sulfur = 28.11
Oxygen = 56.12
We can determine the number of moles of each;
Moles of Aluminium = 15.77 g ÷ 26.98 g/mol
= 0.585 moles
Moles of sulfur = 28.11 g ÷ 32.07 g/mol
= 0.877 moles
Moles of Oxygen = 56.12 g ÷ 16.0 g/mol
= 3.5075 moles
- But, the empirical formula is the simplest whole number ratio of elements in a compound.
- Therefore; we need to get the ratio of moles of the above elements;
Aluminium : Sulfur : Oxygen
0.585 mol : 0.877 mol : 3.5075 mol
0.585/0.585 : 0.877/0.585 : 3.5075/0.585
1 : 1.5 : 6
But, we need whole number ratios, therefore;
= (1 : 1.5 : 6 ) × 2
= 2 : 3 : 12
Therefore; the formula of the compound is Al₂S₃O₁₂
The compound is written as Al₂(SO₄)₃
Thus, the empirical formula of the compound is Al₂(SO₄)₃
