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lawyer [7]
3 years ago
12

A gas mixture at 535.0°C and 109 kPa absolute enters a heat exchanger at a rate of 67.0 m3/hr. The gas leaves the heat exchanger

at 215.0°C. The change in enthalpy of the gas during the cooling process is -5.00 kJ/mol. What is the heat required in kW? Assume the gas behaves ideally and that the changes in kinetic and potential energy are negligible.
Chemistry
1 answer:
SVEN [57.7K]3 years ago
7 0

Answer:

the heat rate required to cool down the gas from 535°C until 215°C is -2.5 kW.

Explanation:

assuming ideal gas behaviour:

PV=nRT

therefore

P= 109 Kpa= 1.07575 atm

V= 67 m3/hr = 18.6111 L/s

T= 215 °C = 488 K

R = 0.082 atm L /mol K

n = PV/RT = 109 Kpa = 1.07575 atm * 18.611 L/s /(0.082 atm L/mol K * 488 K)

n= 0.5 mol/s

since the changes in kinetic and potencial energy are negligible, the heat required is equal to the enthalpy change of the gas:

Q= n* Δh = 0.5 mol/s * (- 5 kJ/mol) =2.5 kW

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Consider the relationship (y+3)2 = b/(x-2), where y and x are variables and bis a constant. On rectangular coordinate paper, wha
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(-1) is the slope of a graph of In(y+3) on the vertical axis versus In(x-2) on the horizontal axis.

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A gamma ray photon has an energy of 4.75 x 10-14 joules. What is the frequency of this radiation?
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The frequency of the radiation is equal to 7.17  \times 10^{19} Hertz.

<u>Given the following data:</u>

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To find the frequency of this radiation, we would use the Planck-Einstein equation.

Mathematically, the Planck-Einstein relation is given by the formula:

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Substituting the given parameters into the formula, we have;

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Frequency, F = 7.17  \times 10^{19} Hertz

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