Answer:
x = 120
Step-by-step explanation:
Let's draw an imaginary dot in the middle of that <u>line</u> which runs between those two parallel lines, and now lets look at it as an angle.
This lines' angle is 180 degrees. Now lets move those two parallel lines together on the imaginary dot in the middle.
We can see that on the left side is one degree and the other side is another, however when we put them together we get the angle measurement of the our line which we identified was 180.
Now that we can see that our two angles must equal 180 when put together we know and can say that:
40 + (x + 20) = 180
So, lets work this out like basic algebra now.
40 + x + 20 = 180
x + 60 = 180
- 60 - 60
x = 120
And voila we have our x value.
Hope this helps :)
Answer:
Below in bold.
Step-by-step explanation:
Nth term an = a1 + d(n - 1) where a1 = term 1 and d = common difference.
Here a1 = 5 and d = 8-5 = 3.
So an = 5 + 3(n - 1)
15th term a15
= 5 + 3(15 - 1)
= 5 + 42
= 47.
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Answer:
x = 1/3
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
4x + 1 = 3 - 2x
<u>Step 2: Solve for </u><em><u>x</u></em>
- Add 2x on both sides: 6x + 1 = 3
- Subtract 1 on both sides: 6x = 2
- Divide 6 on both sides: x = 1/3
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution.</em>
- Substitute: 4(1/3) + 1 = 3 - 2(1/3)
- Multiply: 4/3 + 1 = 3 - 2/3
- Add/Subtract: 7/3 = 7/3
Here we see that 7/3 does indeed equal 7/3.
∴ x = 1/3 is a solution of the equation.
Now that we’ve learned how to solve word problems involving the sum of consecutive integers, let’s narrow it down and this time, focus on word problems that only involve finding the sum of consecutive even integers.
But before we start delving into word problems, it’s important that we have a good understanding of what even integers, as well as consecutive even integers, are.
Even Integers
We know that even numbers are integers that can be divided exactly or evenly by 22. Thus, the general form of the even integer nn, is n = 2kn=2k, where kk is also an integer.
In other words, since even numbers are the multiples of 22, we can represent an even integer nn by 2k2k, where kk is also an integer. So if we have the even integers 1010 and 1616,
