Answer:
First, let's address the general case.
When we have two points (a,b) and (c,d)
The distance between those points can be written as:
D = √( (a - c)^2 + (b - d)^2)
In this case, the points are:
(-2,4) and (2,4)
Then the distance is:
D = √( (-2 - 2)^2 + (4 - 4)^2) = √(-4)^2 = 4.
The equivalent expression to this is: |-2| + |2|
because:
I-2I = 2
I2I = 2
I-2I + I2I = 2 + 2 = 4.
Find the difference per row:
10 seats in the first row
30 seats in the sixth row:
30 -10 = 20 seats difference.
6-1 = 5 rows difference.
20 seats / 5 rows = 4 seats per row.
This means for every additional row, there are 4 more seats per row.
The equation would be:
Sn = S +(n-1)*d
Where d is the difference = 4
S = number of seats from starting row = 10
n = the number of rows wanted
S(11) = 10 + (11-1)*4
S(11) = 10 + 10*4
S(11) = 10 + 40
S(11) = 50
Check:
Row 6 = 30 seats
Row 7 = 30 + 4 = 34 seats
Row 8 = 34 + 4 = 38 seats
Row 9 = 38 + 4 = 42 seats
Row 10 = 42 + 4 = 46 seats
Row 11 = 46 + 4 = 50 seats.
your answer would be D.
4a (4a) + 4a (-5b) + 5b (4a) + 5b (-5b) it is simplified to 16a^2-25b^2
Answer:
z=2
Step-by-step explanation:
I used cross multiplication to solve this.
2/9z=1/9
1(9z)=2(9)
9z=18
z=2
Answer:
ad fk kcfj dlajk jk djkfa ejk fks e
Step-by-step explanation:
