All categories

2 years ago

Find an equation of the line passing through D with a slope of -4/3. please answer fast.

Mathematics

1 answer:

solmaris [256]2 years ago

4 0

Answer:

y = -4/3x - 6

Step-by-step explanation:

since the slope is negative we can infer the line is going downwartd

I’ve attached my work!

Hope it helps :)

If you have any questions or anymore help lmk, happy to help with any school work!!

Have a nice day, you got this !!! <3

You might be interested in

Sin(60-theta)sin(60+theta)

ehidna [41]

Step-by-step explanation:

$\sin(60 - \theta) \sin(60 + \theta) \\ = \{ \sin(60) \cos( \theta) - \sin( \theta) \cos(60) \} \{ \sin(60) \cos( \theta) + \cos(60) \sin( \theta) \} \\ = \{ \frac{ \sqrt{3} }{2} \cos( \theta) - \frac{1}{2} \sin( \theta) \} \{ \frac{ \sqrt{3} }{2} \cos( \theta) + \frac{1}{2} \sin( \theta) \} \\ \\$

from difference of two squares:

${ \boxed{(a - b)(a + b) = ( {a}^{2} - {b}^{2} ) }}$

therefore:

$= \{ {( \frac{ \sqrt{3} }{2}) }^{2} { \cos }^{2} \theta \} - \{ {( \frac{ \sqrt{3} }{2} )}^{2} { \sin }^{2} \theta \} \\ \\ = \frac{3}{4} { \cos }^{2} \theta - \frac{3}{4} { \sin}^{2} \theta$

factorise out ¾ :

$= \frac{3}{4} ( { \cos }^{2} \theta - { \sin}^{2} \theta) \\ \\ = { \boxed{ \frac{3}{4} \cos(2 \theta) }}$

3 0

3 years ago

Read 2 more answers

Equation parallel to y = 3x + 2 and passing through (1, 1)

Kisachek [45]

Answer:

y = 3x - 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x + 2 ← is in slope- intercept form

with slope m = 3

Parallel lines have equal slopes, then

y = 3x + c ← is the partial equation

To find c substitute (1, 1) into the partial equation

1 = 3 + c ⇒ c = 1 - 3 = - 2

y = 3x - 2 ← equation of line

6 0

3 years ago

The area of circle B is 144 pi ft². Find the circumference of circle B.

Sonbull [250]

Circumference = square root (Area * 4 * PI)
circumference = square root ( 452.3893421169 * 4 * PI )
circumference = square root ( 5,684.8921350275)
circumference = 75.3982236862

8 0

3 years ago

Read 2 more answers

HELP PLEASE!! 2 part question

DochEvi [55]

Answer: B. 1 1/2

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

We will now use energy considerations to find the speed of a falling object at impact. Artiom is on the roof replacing some shin

ohaa [14]

Answer:

v = 8.49 m/s rounded off to 3 significant figures

Step-by-step explanation

Using Energy Conservation

U = Tk + Vp (Sum of kinetic Tk Energy and gravitational potential Vp Energy)

At height = 3.67 m, the hammer was still or the velocity was negligible; hence, vi = 0 m/s.
Ui = 0 + mgh
At ground all potential energy is converted to kinetic; hence, Uf = $\frac{1}{2}$ mv².
Since total energy of the system remains constant we equate Ui to Uf.
Ui = Uf
mgh = $\frac{1}{2}$ mv²
After cancelling out masses and making v the subject of the formula we get:

v = $\sqrt[2]{2gh}$ = $\sqrt[2]{2*9.81*3.67}$ = 8.49 m/s rounded off to 3 significant figures

3 0

3 years ago