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irga5000 [103]
2 years ago
12

I would appreciate if somebody help me please!!! Pt2 posted

Chemistry
1 answer:
nignag [31]2 years ago
8 0

The disease prevention methods are as follows:

  • Influenza: Avoid close contact with sick people; Cover your mouth and nose, Clean your hands
  • Salmonella: wash hands properly; keep food area clean; cook food properly
  • Type 2 Diabetes : exercise regularly; reduce sugar intake; quit smoking
  • HIV/AIDS: Avoid sharing of unsterilized sharp objects; avoid unprotected sex; screen blood before transfusion
  • Heart disease: avoid trans fat; exercise regularly; avoid smoking
  • Whooping cough: wear face masks; wash regularly; get vaccinated

<h3>What is the disease prevention?</h3>

Disease prevention refers to the steps taken to protect oneself from developing a particular disease.

The disease prevention methods for the given diseases is as follows:

  • Influenza: Avoid close contact with sick people; Cover your mouth and nose, Clean your hands
  • Salmonella: wash hands properly; keep food area clean; cook food properly
  • Type 2 Diabetes : exercise regularly; reduce sugar intake; quit smoking
  • HIV/AIDS: Avoid sharing of unsterilized sharp objects; avoid unprotected sex; screen blood before transfusion
  • Heart disease: avoid trans fat; exercise regularly; avoid smoking
  • Whooping cough: wear face masks; wash regularly; get vaccinated

In conclusion, disease prevention is the best policy in health care.

Learn more about disease prevention at: brainly.com/question/13341436

#SPJ1

You might be interested in
.400 moles of CO2 gas are confined in a 5.00-liter container at 25 °C. Calculate the pressure exerted in atmospheres and mm Hg.
solong [7]

The pressure exerted by 0.400 moles of carbon dioxide in a 5.00 Liter container at 25 °C would be 1.9563 atm or  1486.788 mm Hg.

<h3>The ideal gas law</h3>

According to the ideal gas law, the product of the pressure and volume of a gas is a constant.

This can be mathematically expressed as:

pv = nRT

Where:

p = pressure of the gas

v = volume

n = number of moles

R = Rydberg constant (0.08206 L•atm•mol-1K)

T = temperature.

In this case:

p is what we are looking for.

v = 5.00 L

n = 0.400 moles

T = 25 + 273

 = 298 K

Now, let's make p the subject of the formula of the equation.

p = nRT/v

  = 0.400 x 0.08206 x 298/5

  = 1.9563 atm

Recall that: 1 atm = 760 mm Hg

Thus:

1.9563 atm = 1.9563 x 760 mm Hg

                   = 1486.788 mm Hg

In other words, the pressure exerted by the gas in atm is 1.9563 atm and in mm HG is 1486.788 mm Hg.

More on the ideal gas law can be found here: brainly.com/question/28257995

#SPJ1

8 0
1 year ago
What is the answer to this chemistry question?
olga_2 [115]

Answer:

The answer to your question is remplacement double

Explanation:

Data

Lead (II) nitrate = Pb(NO₃)₂

Potassium iodide = KI

Process

1.- Write the balanced chemical reaction

             Pb(NO₃)₂  +  2KI  ⇒   PbI₂  +  2KNO₃

2.- Conclusion

This is a remplacement double reaction because there are two reactants that interchange cations and the products are a combination of the reactants.

5 0
4 years ago
How many moles of Ca atoms are in 1 mol of CaSO4?
Galina-37 [17]

Answer:

6.02 x 10²³ atoms

Explanation:

Given parameters:

Number of moles CaSO₄ = 1 mole

Unknown:

Number of Ca atoms in the given compound = ?

Solution:

The given compound is:

          CaSO₄

     1 mole of CaSO₄  is made up of 1 mole of Ca atoms

Now;

   1 mole of any substance contains 6.02 x 10²³ atoms

  1 mole of Ca atoms will also contain 6.02 x 10²³ atoms

7 0
3 years ago
RIGHT ANWSER WILL BE MARKED BRAINLIEST
dybincka [34]

Answer:

11460

Explanation:

4 0
3 years ago
Urea (CH4N2O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH3) with carbon dioxide as follows: 2N
Montano1993 [528]

The question is incomplete, here is the complete question:

Urea (CH₄N₂O) is a common fertilizer that can be synthesized by the reaction of ammonia (NH₃) with carbon dioxide as follows: 2NH₃(aq) + CO₂(aq) → CH₄N₂O(aq) + H₂O(l) In an industrial synthesis of urea, a chemist combines 135.9 kg of ammonia with 211.4 kg of carbon dioxide and obtains 178.0 kg of urea.

Determine the limiting reactant. (express your answer as a chemical formula)

<u>Answer:</u> The limiting reactant is ammonia (NH_3)

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For ammonia:</u>

Given mass of ammonia = 135.9 kg = 135900 g    (Conversion factor:  1 kg = 1000 g)

Molar mass of ammonia = 17 g/mol

Putting values in equation 1, we get:

\text{Moles of ammonia}=\frac{135900g}{17g/mol}=7994.12mol

  • <u>For carbon dioxide gas:</u>

Given mass of carbon dioxide gas = 211.4 kg = 211400 g

Molar mass of carbon dioxide gas = 44 g/mol

Putting values in equation 1, we get:

\text{Moles of carbon dioxide gas}=\frac{211400g}{44g/mol}=4804.54mol

The given chemical reaction follows:

2NH_3(aq.)+CO_2(aq,)\rightarrow CH_4N_2O(aq.)+H_2O(l)

By Stoichiometry of the reaction:

2 moles of ammonia reacts with 1 mole of carbon dioxide

So, 7994.12 moles of ammonia will react with = \frac{1}{2}\times 7994.12=3997.06mol of carbon dioxide

As, given amount of carbon dioxide is more than the required amount. So, it is considered as an excess reagent.

Thus, ammonia is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reactant is ammonia (NH_3)

5 0
3 years ago
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