The whole sentence is written as:
Alcohol is a very common substance, which is surprising considering its many harmful effects.
From the sentence, the dependent clause would be "which is surprising considering its many harmful effects." The dependent clause is a part of a sentence which is not understandable without the whole sentence.
The volume of the 0.130 M sulfuric acid, H₂SO₄ required to react completely with 65.9 g sodium hydroxide, NaOH is 6.34 L
- We'll begin by calculating the number of mole of in 65.9 g sodium hydroxide, NaOH. This can be obtained as follow:
Mass of NaOH = 65.9 g
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
<h3>Mole of NaOH =?</h3>
Mole = mass / molar mass
Mole of NaOH = 65.9 / 40
<h3>Mole of NaOH = 1.6475 mole</h3>
- Next, we shall determine the number of mole of H₂SO₄ needed to react with 1.6475 mole of NaOH. This can be obtained as follow:
2NaOH + H₂SO₄ —> Na₂SO₄ + 2H₂O
From the balanced equation above,
2 moles of NaOH reacted with 1 mole of H₂SO₄.
Therefore,
1.6475 mole of NaOH will react with =
= 0.82375 mole of H₂SO₄.
- Finally, we shall determine the volume of 0.130 M sulfuric acid, H₂SO₄ required for the reaction.
Molarity of H₂SO₄ = 0.130 M
Mole of H₂SO₄ = 0.82375 mole
<h3>Volume of H₂SO₄ =? </h3>
Volume = mole / Molarity
Volume of H₂SO₄ = 0.82375 / 0.130
<h3>Volume of H₂SO₄ = 6.34 L </h3>
Therefore, the volume of the 0.130 M sulfuric acid, H₂SO₄ required for the reaction is 6.34 L
Learn more: brainly.com/question/7882345
From the chemical equation given:
H2SO4+2KOH--->K2SO4+2H2O
the two reactants, H2SO4 and KOH, are in 1:2 stoichiometric ratio.
No. of moles of KOH = 2* no. of moles of H2SO4
=2*0.1*0.033
The concentration of KOH = no. of moles / volume
=2*0.1*0.033/0.05
=0.132M
Answer:
2Ag(s) + Cu^2+(aq) ----------> 2Ag^+(aq) + Cu(s)
Explanation:
Ag(s)/Ag^+ (aq) is the anode as shown while Cu^2+(aq)/Cu^2(s) is the cathode.
E°cell= E°cathode -E°anode= 0.34 -0.80= -0.5V
The cell is not spontaneous as written because E°cell is negative. This implies that the electrodes of the cell must be interchanged to make the cell spontaneous.
Technetium, with atomic number denoted Z43, is the lowest-numbered element in the periodic table of which all isotopes are radioactive