All categories

3 years ago

True or False When one side of a molecule is electronegative (δ-) and the other side of the

Chemistry

1 answer:

lesya [120]3 years ago

8 0

Answer:

True; When one side of a molecule is electronegative (δ-) and the other side of the

molecule is electropositive (δ+), it is said to have a dipole moment.

Explanation:

A dipole moment exists in a molecule as a result of differences in the electronegativity values between the atoms of the elements involved in the chemical bonding.

When a strogly electronegative atom such as oxygen or chlorine is chemically bonded to a less electronegative or an electropositive atom such as hydrogen, there is an uneven sharing of the electrons involved in the bonding. The more electronegative atoms tends to draw the shared electrons mostly to themselves. This induces a partially negative charge (δ-) on them while leaving the electropositive atoms with a partially positive charge (δ+).

Water is an example of a molecule having a dipole moment. The oxygen atoms are more electronegative than hydrogen and as such draw the shared electrons to themselves more, inducing a partial positive charge (δ+) on the hydrogen atoms while they themselves develop a partial negative charge (δ-).

You might be interested in

he solution is said to be an ideal solution, only when the intermolecular forces of attraction between A-A, B- B and A- B are ne

KengaRu [80]

Answer:True

Explanation:

A ideal solution is a solution which obeys Raoults law on almost every concentration and temperature range.

Ideal solutions are formed by mixing those solute and solvent which has identical molecular properties.

Lets take A be the solute and B be the solvent so to form a ideal solution from these components the solute-solute(A-A) molecular interaction and solvent -solvent (B-B) molecular interactions must be identical with the solute solvent interaction(A-B).

The solute-solute molecular interaction ,solute-solvent molecular interaction and solvent-solvent molecular interaction must be equal in order to form a ideal solution.

The enthalpy of mixing and volume of mixing of ideal solution is zero.

enthalpy of mixing is the amount of energy released on mixing a solute and solvent and in case of ideal solutions it is zero.

Volume of mixing is change in volume on mixing a solute and solvent.

3 0

4 years ago

The dehydrogenation of benzyl alcohol to make the flavoring agent benzaldehyde is an equilibrium process described by the equati

valkas [14]

Answer:

(a) $p_{C6H5CH2OH}=2.14x10^{-3}atm$

(b) $Dissociation =0.99$

Explanation:

Hello,

(a) In this case, for the given chemical reaction, the law of mass action becomes:

$Kc=\frac{[C6H5CHO][H2]}{[C6H5CH2OH]}$

In such a way, as 1.20 g of benzyl alcohol are placed into a 2.00-L vessel, the initial concentration is:

$[C6H5CH2OH]_0=\frac{1.20g*\frac{1mol}{108.14g} }{2.00L} =5.55x10^{-3}M$

Hence, by writing the law of mass action in terms of the change $x$ due to equilibrium:

$Kc=\frac{(x)(x)}{5.55x10^{-3}-x}=0.558$

Solving for $x$ by using a quadratic equation one obtains:

$x=5.50x10^{-3}M$

Thus, the equilibrium concentration of benzyl alcohol is computed:

$[C6H5CH2OH]_{eq}=5.55x10^{-3}M-5.50x10^{-3}M=5x10^{-5}M$

With that concentration the partial pressure results:

$p_{C6H5CH2OH}=[C6H5CH2OH]_{eq}RT =5x10^{-5}\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*523K \\p_{C6H5CH2OH}=2.14x10^{-3}atm$

(b) Now, the fraction of benzyl alcohol that is dissociated relates its equilibrium concentration with its initial concentration:

$Dissociation=\frac{C6H5CH2OH_{eq}}{C6H5CH2OH_0} =\frac{5.50x10^{-3}M}{5.55x10^{-3}M} =0.99$

Best regards.

3 0

3 years ago

Read 2 more answers

Calculate the average atomic mass of B. The isotopes and abundances are 10B, 19.80% and 11B, 80.20%. Round answer to 3 significa

timama [110]

Given,

The two isotopes of B are 10B and 11B

% abundance of 10B = 19.80

% abundance of 11B = 80.20

Average atomic mass of B

= $\frac{(mass of 10B)(abundance of 10B) + (mass of 11B)(abundance of 11B)}{100}$

= $\frac{(10)(19.80) + (11)(80.20)}{100}$

= $\frac{198 + 882.2}{100}$

= $\frac{1080.2}{100}$

= 10.802

Therefore, the average atomic mass of B is 10.802 u

8 0

4 years ago

Read 2 more answers

Assuming ideal behavior, how many moles of argon would you need to fill a 14.0×12.0×10.0 ft room? assume atmospheric pressure of

UNO [17]

We use the formula:

PV = nRT

First let us get the volume V:

volume = 14 ft * 12 ft * 10 ft = 1,680 ft^3

Convert this to m^3:

volume = 1680 ft^3 * (1 m / 3.28 ft)^3 = 47.61 m^3

n = PV / RT

n = (1 atm) (47.61 m^3) / (293.15 K * 8.21x10^-5 m3 atm / mol K)

5 0

3 years ago

Tasting is not advisable method for identifying substance?? True or False

NARA [144]

False you should never taste something if you don’t know what it is

4 0

3 years ago