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Goryan [66]
3 years ago
8

At the equilibrium point in the decomposition of phosphorus pentachloride to chlorine and phosphorus trichloride, the following

concentrations are obtained: 0.010 mol/L PCl5, 0.15 mol/l PCl3 and 0.37 mol/L Cl2. Determine the Keq for the reaction
Chemistry
1 answer:
Hitman42 [59]3 years ago
5 0

Answer: K_{eq} for the reaction is 5.55

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

                        PCl_5(g)\rightleftharpoons PCl_3(g)+Cl_2(g)          

At eqm. conc.   (0.010) M     (0.15)  M   (0.37) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[Cl_2]\times [PCl_3]}{[PCl_5]}

Now put all the given values in this expression, we get :

K_c=\frac{(0.37)\times (0.15)}{(0.010)}

K_c=5.55

Thus the K_{eq} for the reaction is 5.55

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How much heat is required to warm 50.0 g of ice from -10.0oC to 0.00oC, melt the ice, warm the water from 0.00oC to 100.0oC, boi
ludmilkaskok [199]

The total heat required to convert the ice to steam is 155,000 J.

The given parameters:

  • <em>Mass of the ice, m = 50 g</em>
  • <em>Initial temperature of the ice, t = -10 ⁰C</em>
  • <em>Final temperature of the ice, T = 0⁰C, 100⁰C and 120⁰C</em>
  • <em>Specific heat capacity of water = 4.184 J/g⁰C</em>
  • <em>Heat of fusion of ice, = 333.55 J/g</em>
  • <em>Heat of vaporization, = 2,230 J/g</em>

<em />

The heat required to raise the temperature to 0⁰C is calculated as;

Q  = mc\Delta t\\\\Q_1 = 50 \times 4.184 \times (0 - (-10))\\\\Q_1 = 2092 \ J

The  heat required to melt the ice is calculated as follows;

Q_2 = mL_f\\\\Q_2 = 50 \times 333.55 \\\\Q_2 = 16,677.5 \ J

The heat raise the temperature to 100⁰C is calculated as;

Q_3 = 50 \times 4.184 \times (100 - 0)\\\\Q_3 = 20,920 \ J

The  heat required to boil the water is calculated as follows;

Q_4 = mL_v\\\\Q_4 = 50 \times 2230\\\\4_4 = 111,500 \ J

The heat raise the temperature to 120⁰C is calculated as;

Q_5 = 50 \times 4.184 \times (120 - 100)\\\\Q_5 = 4,184 \ J

The total heat required is calculated as follows;

Q_t = Q_1 + Q_2 + Q_3 + Q_4 + Q _5 \\\\Q_t  = 2092 + 16,677.5 + 20,920 + 111,500 + 4,184\\\\Q_t = 155,373.5 \ J\\\\Q_t \approx 155,000 \ J

Learn more about heat capacity here: brainly.com/question/16559442

4 0
3 years ago
Calculate how much acetylene (C2H2) will be produced from 358 g of H2O and an excess of CaC2 if the percent yield for this react
Ket [755]

Answer:

244.7 g of acetylene

Explanation:

The balanced reaction equation is shown below;

2H20 (l) + CaC2 (s) → Ca(OH)2 (s) + C2H2 (g)

Number of moles of were reacted = reacting mass/molar mass = 358g/18gmol-1 = 19.89 moles of water

From the balanced reaction equation;

2 moles water yields 1 mole of acetylene

19.89 moles of water will yield 19.89 × 1/2 = 9.945 moles of acetylene

Theoretical yield of acetylene = 9.945 moles of acetylene × molar mass of acetylene

Molar mass of acetylene = 26.04 g/mol

Theoretical yield of acetylene = 9.945 moles of acetylene × 26.04 g/mol

Theoretical yield of acetylene = 258.9678 g of acetylene

% yield = actual yield/ theoretical yield × 100

94.5 = actual yield/258.9678 g × 100

Actual yield= 94.5 × 258.9678 g/100

Actual yield = 244.7 g of acetylene

6 0
3 years ago
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Answer:

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7 0
3 years ago
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A solution is made by mixing 31 g of heptane C7H16 and 42 g of chloroform CHCl3.
levacccp [35]

Answer:

The mol fraction of heptane in this solution is 0.47

Explanation:

Step 1: Data given

Mass of heptane = 31.00 grams

Molar mass of heptane = 100.21 g/mol

Mass of chloroform = 42.00 grams

Molar mass of chloroform = 119.38 g/mol

Step 2: Calculate moles heptane

moles heptane = 31.00 grams / 100.21 g/mol

moles heptane = 0.309 moles

Step 3: Calculate moles chloroform

moles chloroform = 42.00 grams / 119.38 g/mol

moles chloroform = 0.352 moles

Step 4: Calculate total moles

Total moles = moles heptane + moles chloroform

Total moles = 0.309 moles + 0.352 moles = 0,661 moles

Step 5: Calculate mol fraction of heptane

Mol fraction heptane = moles heptane / total moles

Mol fraction heptane = 0.309 moles / 0.661 moles

Mol fraction heptane = 0.47

The mol fraction of heptane in this solution is 0.47

8 0
4 years ago
Read 2 more answers
A gas at 300 k and 4.0 atm is moved to a new location with a temperature of 250 k. the volume changes from 5.5 l to 2.0 l. what
ella [17]

Answer:

9.17 atm

Explanation:

To find the new pressure of the gas, you need to use the following manipulated formula:

P₁V₁ / T₁ = P₂V₂ / T₂

In this formula,

P₁ = initial pressure (atm)              P₂ = new pressure (atm)

V₁ = initial volume (L)                    V₂ = new volume (L)

T₁ = initial temperature (K)            T₂ = new temperature (K)

Because you have been given values for all of the variables except for the new pressure, you can substitute them into the equation and simplify.

P₁ = 4.0 atm                                  P₂ = ? atm

V₁ = 5.5 L                                      V₂ = 2.0 L

T₁ = 300 K                                     T₂ = 250 K

P₁V₁ / T₁ = P₂V₂ / T₂                                                     <----- Given formula

(4.0 atm)(5.5 L) / (300 K) = P₂(2.0 L) / (250 K)           <----- Insert variables

0.073333 = P₂(2.0 L) / (250 K)                                   <----- Simplify left side

18.33333 = P₂(2.0 L)                                     <----- Multiply both sides by 250

9.17 = P₂                                                        <----- Divide both sides by 2.0

5 0
2 years ago
Read 2 more answers
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