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2 years ago

I need it please !!!

Chemistry

1 answer:

anyanavicka [17]2 years ago

6 0

Answer:

im pretty sure its 2...

Explanation:

if its wrong im sorry

if its right brainliest pls?

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PLEASE HELP ME

ki77a [65]

Answer:

1.15 atm

Explanation:

According to Dalton's law of partial pressures, the total pressure is the sum of all the partial pressures of the gases present in the mixture.

Therefore we have:

Total pressure = partial pressure of carbon monoxide + partial pressure of oxygen + partial pressure of carbon dioxide

We were given the following:

Total pressure = 2.45 atm

Pressure of oxygen = 0.65 atm

Pressure of carbon monoxide = x

Pressure of carbon dioxide = 0.65 atm

Therefore:

2.45 = x + 0.65 + 0.65

2.45 = x + 1.3

x = 2.45 - 1.3

x = 1.15 atm

6 0

3 years ago

How many moles of H2 and N2 can be formed by the decomposition of 0.145 mol of ammonia, NH3 ?

zepelin [54]

Answer:

Explanation:

The moles of H2 and N2 are as follows respectively, 0.3915mol of H2 and 0.1305 mol of N2.

5 0

2 years ago

The body gets rid of lactic acid in a chemical pathway that requires ___________. A. carbon dioxide . B. oxygen . C. amino acids

Luden [163]

The body gets rid of acid in a chemical pathway that requires oxygen. The correct answer is B, oxygen.

5 0

2 years ago

What are the names of the components (each shown with a leader and a line) of a circuit shown in the diagram? Please help!!!!

alekssr [168]

Maybe: Battery, wire, lamp and switch

6 0

2 years ago

The solubility of water in diethyl ether has been reported to be 1.468 % by mass.' Assuming that 23.0 mL of diethyl ether were a

melomori [17]

Explanation:

As it is given that solubility of water in diethyl ether is 1.468 %. This means that in 100 ml saturated solution water present is 1.468 ml.

Hence, amount of diethyl ether present will be calculated as follows.

(100ml - 1.468 ml)

= 98.532 ml

So, it means that 98.532 ml of diethyl ether can dissolve 1.468 ml of water.

Hence, 23 ml of diethyl ether can dissolve the amount of water will be calculated as follows.

Amount of water = $\frac{1.468 ml \times 23 ml}{98.532 ml}$

= 0.3427 ml

Now, when magnesium dissolves in water then the reaction will be as follows.

$Mg + H_{2}O \rightarrow Mg(OH)_{2}$

Molar mass of Mg = 24.305 g

Molar mass of $H_{2}O$ = 18 g

Therefore, amount of magnesium present in 0.3427 ml of water is calculated as follows.

Amount of Mg = $\frac{24.305 g \times 0.3427 ml}{18 g}$

= 0.462 g

6 0

3 years ago