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2 years ago

5

Can someone please help me

2 answers:

Lelu [443]2 years ago

8 0

1 true
2 false
3 false
4 true

Nana76 [90]2 years ago

7 0

Answer:

1 true

2 false

3 false

4 true

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Someone plz help me

topjm [15]

x = 375 and y = 6300. Option C.

Step-by-step explanation:

From the given data we need to find the value of x and y.

First, we will find out the ratio of area and the force.

$\frac{Area}{Force} = \frac{125}{1875} =\frac{150}{2250} =\frac{175}{2625}$ = $\frac{1}{15}$

So,

$\frac{x}{5625} = \frac{1}{15}$

or, x = $\frac{5625}{15}$ = 375

Again,

$\frac{420}{y} = \frac{1}{15}$

or, y = 420×15 = 6300

Hence,

x = 375 and y = 6300.

7 0

3 years ago

The sum of two numbers is 43 and the difference is 13 what are the numbers

Zinaida [17]

Answer: 1. 28 2. 25

Hope this helps!

Didn't know if you wanted the explanation or not, so sorry. But I can put an explanation if you need it.

6 0

3 years ago

juin [17]

C kinetic energy. As it loses potential energy, it gain kinetic energy

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3 years ago

Read 2 more answers

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

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3 years ago

Find -3 3/4 +1/2, i-Ready quiz

Fofino [41]

Answer: I think the answer is -3 2/5✨

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3 years ago