What integer is greater than -5
1 answer:
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Answer:
x = {-5π/4, -3π/4, 3π/4, 5π/4}
Step-by-step explanation:
You know that sec(x) = 1/cos(x), so this is equivalent to ...
cos(x) = -1/√2
The cosine has a magnitude of 1/√2 for an angle of 45°, or π/4 radians. It is negative in the 2nd and 3rd quadrants. Angles in those quadrants that have a reference angle of π/4 are ...
3π/4, 5π/4
We also want angles in the range -2π to 0, so all of the solutions will be ...
sec(x) = -√2 for x = {-5π/4, -3π/4, 3π/4, 5π/4}
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We like to use the x-intercept as the solution when graphing, so we write the given equation as ...
sec(x) +√2 = 0
The graph verifies the above solutions.
Answer:
Step-by-step explanation:
Step 1:
Let us find the missing side. We know this is a <u>right triangle</u>, so we can use the pythagorean thereom to find the last side. Let us set 12 as variable <em>a</em>, 20 as variable <em>c</em>, and the unknown side as variable <em>b</em>.
We do know that a <u>length can never be negative</u>, so the side <em>b</em> would be 16.
Step 2:
According to SOHCAHTOA, cosine is utilizes the adjacent and hypotenuse of the given angle theta. Let us write the equation:
<em>I hope this helps! Let me know if you have any questions :)</em>