-(4x - 5) + 16x ≥ -31 can you solve this inequality equation?
1 answer:
You might be interested in
State the vertex and axis of symmetry of the graph of y=ax^2+c
General form of quadratic equation is
There is no bx in our given equation, so we put 0x
Given equation can be written as
a=a , b=0
Now we use formula to find vertex
Now we plug in 0 for 'a' and find out y
So our vertex is (0,c)
The axis of symmetry at x coordinate of vertex
So x=0 is our axis of symmetry