Answer:
y=sec(x) + 1
Step-by-step explanation:
The Sec(x) = 1/Cos(x) which has a minimum of +1 when positive, and -1 when negative. Adding +1 to it gives a range of (-∞,0) and when negative (2,∞)
8/10 = 0.8
Therefore, 0.8 (8/10) is put on the number line shown below.
Answer:
None
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 4x - 2
x = 3
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em> [Function]: f(3) = 4(3) - 2
- Multiply: f(3) = 12 - 2
- Subtract: f(3) = 10
• The value of the discriminant ,D= -16
,
• The solution to the quadratic equation is
Step - by - Step Explanation
What to find?
• The discriminant d= b² - 4ac
,
• The solution to the quadratic equation.
Given:
5x² - 2x + 1=0
Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0
a=5 b=-2 and c=1
Uisng the quadratic formula to solve;
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
The discriminant D=b² - 4ac
Substitute the values into the discriminant formula and simplify.
D = (-2)² - 4(5)(1)
D = 4 - 20
D = -16
We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;
![x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-2%29%5Cpm%5Csqrt%5B%5D%7B-16%7D%7D%7B2%285%29%7D)
Note that:
√-1 = i
![x=\frac{2\pm\sqrt[]{16\times-1}}{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2%5Cpm%5Csqrt%5B%5D%7B16%5Ctimes-1%7D%7D%7B10%7D)
![x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B2%5Cpm%5Csqrt%5B%5D%7B16%7D%5Ctimes%5Csqrt%5B%5D%7B-1%7D%7D%7B10%7D)
That is;
Answer:
The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation.
So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation. And since x + y = 8, you are adding the same value to each side of the first equation.
