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nexus9112 [7]
2 years ago
13

Subtracting polynomial expressions

Mathematics
2 answers:
Licemer1 [7]2 years ago
8 0

Answer:7m^5 - 3m^3 + 9

Step-by-step explanation: You’d have to remove the brackets, but remember that the second has to have everything multiplied by -1, because there’s a minus sign in front of the second bracket. Then you’d group like terms, then add or subtract. Here’s the step by step

6m^5 + 3 - m^3 - 4m + m^5 - 2m^3 + 4m + 6

2. 6m^5 + m^5 - 2m^3 - m^3 + 4m - 4m + 6 + 3

Subtract or add what’s needed, which would be figures with the same variable and coefficient.

3. 7m^5 - 3m^3 + 9

After this, there’s nothing you can add, since the remaining figures don’t have the same variable.
Hope it’s clear and this wasn’t that long

vfiekz [6]2 years ago
3 0
The correct answer would be 7m^5-3m^3+9
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Answer:

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Step-by-step explanation:

Calculate the gradient m using the gradient formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 1, 2) and (x₂, y₂ ) = (3, 1) ← 2 points on the line

m = \frac{1-2}{3-(-1)} = \frac{-1}{3+1} = - \frac{1}{4}

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2 years ago
If you could show as much work as possible that would be amazing!!
Nikitich [7]

Answers:

<u>Reduce:</u>

Here we gave to simplify the expressions:

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Grouping similar terms:

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Applying common factor x^{2} in the first parenthesis and common factor 2 in the second parenthesis:

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11) y^{3}+\frac{27}{y^{2}}+2y-3

Rearranging the terms:

(y^{3}+2y)+(\frac{27}{y^{2}}-3)

Applying common factor y in the first parenthesis and common factor 3 in the second parenthesis:

y(y^{2}+2)+3(\frac{9}{y^{2}}-1) This is the answer

<u>Multiply:</u>

19) (\frac{12a^{9}u^{7}}{15 c})(\frac{3c^{4}}{21a^{13 u^{8}}})

Multiplying both fractions:

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Dividing numerator and denominator by 3 and simplifying:

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Operating with cross product:

x^{2} (x^{2}-3-7x) x(x^{4}-9x^{3}+35-18x^{2})

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Grouping similar terms and factoring:

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<u>Divide:</u>

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Simplifying:

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Applying the distributive property in numerator and denominator:

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