Answer:
There are 4 significant figures.
Explanation:
- Any zeros that come before any non-zero number are never significant.
- Zeros that are in between any non-zero numbers are always significant.
- Zeros that come after any non-zero are ONLY significant is there is a decimal point present. (In this case, there is.)
The significant figures are underlined :
0 . 0 <u>9</u> <u>0</u> <u>5</u> <u>0</u>
Solute is the term used for a substance being dissolved in a solution.
The hybridization for C in acetylene, HCCH, or C₂H₂ is 'sp'.
Discussion:
There are three different forms of hybridization -
- sp- The first occurs when two carbon atoms are triple linked.
- sp₂- When two carbon atoms are double-bonded to one another, this is known as sp₂.
- sp₃- When a single bond joins two carbon atoms, this is known as sp₃.
In the case of acetylene(HCCH or C₂H₂):
- The carbon atom requires additional electrons to establish four bonds with hydrogen and other carbon atoms in the synthesis of C₂H₂. One 2s₂ pair is consequently transferred to the vacant 2pz orbital. Each carbon has two sp hybrid orbitals after the 2s orbital in each atom combines with one of the 2p orbitals.
- As a result of the atoms' symmetrical alignment in a single plane, C₂H₂ possesses a linear molecular structure. Due to their lower electronegative nature than Hydrogen atoms, all Carbon atoms are situated near the center of the Lewis structure of C₂H₂.
H-C≡C-H
Therefore, it is concluded from the above discussion that the hybridization type of acetylene is 'sp'.
Learn more about hybridization here:
brainly.com/question/14140731
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Answer:
The correct answer is <u>Option</u><u>-</u><u>B</u> (Convert grams of Mg to moles)
Explanation:
In stoichiometry problems the first step is always to balance the given unbalanced chemical equation. In our case the given equation is already balanced hence, we looked for the second step.
As Niven wants to calculate the mass of MgO (which is the product) with respect to Mg (reactant) hence here comes another important rule. In such cases if one wants to compare masses of two reactants or reactant product. or product product then one should first convert the given mass into moles, also the same conversion for the second mass and then compare the moles and at last convert the moles back into mass. So, the flow chart should be like,
Mass (Mg) → Moles (Mg) : (MgO) Moles ← (MgO) Mass
After finding moles following step take place,
Moles (MgO) → Mass (MgO)