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azamat
3 years ago
7

How does the arrangement of particles in a gas differ from the arrangements in liquids and solids?

Chemistry
1 answer:
Paladinen [302]3 years ago
3 0
The arrangement of particles in a gas is random. they have no orderly arrangement and are free to move around while the particles in solid are in an orderly and rigid arrangement and cannot move about. particles in liquid are also arranged orderly but are not rigid
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The fraction of a radioactive isotope remaining at time t is (1/2)^t/t1/2 where t1/2 is the half-life. If the half-life of carbo
Katena32 [7]

Answer:

a) 1.065\times 10^{-8}fraction of carbon−14 in a piece of charcoal remains after 14.0 years.

b) 0.000\times 10^{-3}fraction of carbon−14 in a piece of charcoal remains after  1.900\times 10^4 years

c) 0.0000\times 10^{-4}fraction of carbon−14 in a piece of charcoal remains after  1.0000\times 10^5 years.

Explanation:

The fraction of a radioactive isotope remaining at time t is given by:

[A]=\frac{(\frac{1}{2})^t}{t_{\frac{1}{2}}}

Taking log both sides:

\log [A]=t\log[\frac{1}{2}]-\log [t_{\frac{1}{2}}]

[A] =  fraction at given time t

t_{\frac{1}{2}} = half life of the carbon−14 =5,730 years

a)When , t = 14 years

\log [A]=t\log[\frac{1}{2}]-\log [t_{\frac{1}{2}}]

\log [A]= 14 years\times (-3010)-\log [5,730 years]

[A]=1.065\times 10^{-8}

b)When , t = 1.900\times 10^4 years

\log [A]=t\log[\frac{1}{2}]-\log [t_{\frac{1}{2}}]

\log [A]= 1.900\times 10^4 years\times (-3010)-\log [5,730 years]

[A]=0.000\times 10^{-3} [/tex

c)When , t = 1.0000\times 10^5 years

\log [A]=t\log[\frac{1}{2}]-\log [t_{\frac{1}{2}}]

\log [A]= 1.0000\times 10^5 years\times (-3010)-\log [5,730 years]

[A]=0.0000\times 10^{-4}

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Which metal would have more luster, zinc (30) or scandium (21)?​
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Answer:

i say zinc would

Explanation:

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Name two physical properties that could be used to distinguish between water and ethanol.
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