All categories

4 years ago

How does the arrangement of particles in a gas differ from the arrangements in liquids and solids?

1 answer:

3 0

The arrangement of particles in a gas is random. they have no orderly arrangement and are free to move around while the particles in solid are in an orderly and rigid arrangement and cannot move about. particles in liquid are also arranged orderly but are not rigid

You might be interested in

A student decreases the temperature of a 556 c m cubed balloon from 278 K to 231 K. Assuming constant pressure, what should the

a_sh-v [17]

Answer:

The new volume of the balloon be $462\ cm^3$ .

Explanation:

We have,

Initial volume is 556 cm ³

The temperature of the balloon decreases from 278 K to 231 K.

We need to find the new volume of the balloon if the pressure is constant.

The Charles law states that at constant pressure, the volume of gas is directly proportional to its temperature i.e.

$V\propto T$ , P is constant

$\dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}$

$V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{556\times 231}{278}\\\\V_2=462\ cm^3$

So, the new volume of the balloon be $462\ cm^3$ .

3 0

3 years ago

What are atoms help

Savatey [412]

a b c d no a no b yes c no d ok

8 0

3 years ago

An excess of NiCO3, 12 g, was added to 40cm cube of sulpheric acid, 2.0 mol/dm cube. The unreacted nickel carbonate was filtered

Zepler [3.9K]

Calculate the number of moles reacted - 0.08 moles
Calculate the mass of nickel carbonate reacted - 0.08 * 119g
Calculate the mass of unreacted nickel carbonate - 12.0 - (0.08 * 119)g

1 mole of NiCO3 reacts with 1 mole of H2SO4

3 0

3 years ago

Please help me I really don’t understand

Leokris [45]

I dont understand life, for example, look at my username.

4 0

4 years ago

An atom of helium has a radius of 31. pm and the average orbital speed of the electrons in it is about 4.4x 10 m/s Calculate the

otez555 [7]

The question is incomplete, here is the complete question:

An atom of helium has a radius of 31. pm and the average orbital speed of the electrons in it is about $4.4\times 10^6m/s$ . Calculate the least possible uncertainty in a measurement of the speed of an electron in an atom of helium. Write your answer as a percentage of the average speed, and round it to 2 significant digits

<u>Answer:</u> The percentage of average speed is 41 %

<u>Explanation:</u>

We are given:

Radius of helium atom = 31 pm = $31\times 10^{-12}m$ (Conversion factor: $1m=10^{12}pm$ )

So, diameter of helium atom = $(2\times r)=(2\times 31\times 10^{-12})=64\times 10^{-12}m$

The diameter of the atom will be equal to the uncertainty in position.

The equation representing Heisenberg's uncertainty principle follows:

$\Delta x.\Delta p=\frac{h}{2\pi}$

where,

$\Delta x$ = uncertainty in position = d = $64\times 10^{-12}m$

$\Delta p$ = uncertainty in momentum = $m\Delta v$

m = mass of electron = $9.1095\times 10^{-31}kg$

h = Planck's constant = $6.627\times 10^{-34}kgm^2/s^2$

Putting values in above equation, we get:

$64\times 10^{-12}m\times 9.1095\times 10^{-31}kg\times \Delta v=\frac{6.627\times 10^{-34}kgm^2/s}{2\times 3.14}\\\\\Delta v=\frac{6.627\times 10^{-34}kgm^2/s^2}{2\times 3.14\times 64\times 10^{-12}m\times 9.1095\times 10^{-31}kg}=1.81\times 10^6m/s$

To calculate the percentage of average speed, we use the equation:

$\text{Percentage of the average speed}=\frac{\text{Uncertainty in velocity}}{\text{Average orbital speed}}\times 100$

We are given:

Average orbital speed = $4.4\times 10^6m/s$

Putting values in above equation, we get:

$\text{Percentage of the average speed}=\frac{1.81\times 10^6m/s}{4.4\times 10^6m/s}\times 100\\\\\text{Percentage of the average speed}=41.\%$

Hence, the percentage of average speed is 41 %

3 0

4 years ago