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Yuri [45]
3 years ago
7

Although Rutherford is credited with the famous gold foil scattering experiment, he didn’t actually conduct this experiment hims

elf. It was done by two of his assistants, Hans Geiger and Ernest Marsden. Do you think it was fair to name the experiment after Rutherford while ignoring the other two scientists? Why or why not? Give credible arguments for your answer
Chemistry
1 answer:
Dmitrij [34]3 years ago
3 0
Although he did not do the experiment himself, he had come up with the idea of what to do and how to do it. I think that only Rutherford receiving credit is okay as the assistants did not do anything to contribute to the actual idea of the experiment.
For example, we credit the invention of the iPhone to Steve Jobs, the engineers of Apple, the designers, etc. - those with actual contributions to the invention and the ideas and not the Chinese factory workers - those who construct the iPhone itself. 
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Wittaler [7]

Answer:

pH = 6.999

The solution is acidic.

Explanation:

HBr is a strong acid, a very strong one.

In water, this acid is totally dissociated.

HBr + H₂O  →  H₃O⁺  +  Br⁻

We can think pH, as - log 7.75×10⁻¹² but this is 11.1

acid pH can't never be higher than 7.

We apply the charge balance:

[H⁺] = [Br⁻] + [OH⁻]

All the protons come from the bromide and the OH⁻ that come from water.

We can also think [OH⁻] = Kw / [H⁺] so:

[H⁺] = [Br⁻] + Kw / [H⁺]

Now, our unknown is [H⁺]

[H⁺] =  7.75×10⁻¹² + 1×10⁻¹⁴ / [H⁺]

[H⁺] = (7.75×10⁻¹² [H⁺] + 1×10⁻¹⁴) /  [H⁺]

This is quadratic equation:  [H⁺]² - 7.75×10⁻¹² [H⁺] - 1×10⁻¹⁴

a = 1 ; b = - 7.75×10⁻¹² ; c = -1×10⁻¹⁴

(-b +- √(b² - 4ac) / (2a)

[H⁺] = 1.000038751×10⁻⁷

- log [H⁺] = pH → 6.999

A very strong acid as HBr, in this case, it is so diluted that its pH is almost neutral.

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