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Rina8888 [55]
3 years ago
6

The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is

0.54 M? The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is 0.54 M? 4.7 s 0.49 s 1.0 s 1.3 s 1.8 s
Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Answer:

The half life time of first order reaction is 1.3 sec

Explanation:

Given:

First order rate constant K = 0.54 M^{-1} s^{-1}

Initial concentration = 0.54 M

From the formula of first order half life time,

  K = \frac{0.693}{t_{\frac{1}{2} } }

So half life time is given by,

{t_{\frac{1}{y2} } } = \frac{0.693}{0.54}

{t_{\frac{1}{y2} } }  = 1.3 sec

Therefore, the half life time of first order reaction is 1.3 sec.

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A gas sample has a temperature of 22c with an unknown volume. The same gas has a volume of 456 mL when the temperature is 86c wi
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Answer:

V₁  = 374.71  mL

Explanation:

Given data:

Initial volume of gas= ?

Initial temperature = 22°C

Final temperature = 86°C

Final volume = 456 mL

Solution:

Initial temperature = 22°C (22+273 = 295 k)

Final temperature = 86°C (86+273 = 359 k)

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₁ = V₂T₁ /T₂

V₁  = 456 mL × 295 K / 359 k

V₁  = 134520 mL.K /  359 k

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Scientists think the earth is approximately how old?
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Balance each of these equations.
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8 0
2 years ago
Iron fluoride (FeF2) dissociates according to the following equation:
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Answer:

S = 0.788 g/L

Explanation:

The solubility product (Kps) is an equilibrium solubization constant, which can be calculated by the equation:

Kps = \frac{[product]^x}{[reagent]^y}

Where x and y are the stoichiometric coefficients of the product and the reagent, respectively. Because of the aggregation form, the concentration of solids is always equal to 1 for use in this equation.

Analyzing the equation, we see that for 1 mol of Fe^{+2} is necessary 2 mols of F^-, so if we call "x" the molar concentration of Fe^2, for F^- we will have 2x, so:

Kps = [Fe^{+2}].[F^-]^2\\\\2.36x10^{-6} = x(2x)^2\\\\2.36x10^{-6} = 4x^3\\\\x^3 = 5.9x10^{-7}\\\\x = \sqrt[3]{5.9x10^{-7}} \\\\x = 8.4x10^{-3} mol/L

So, to calculate the solubility (S) of FeF2, which is in g/L, we multiply this concentration by the molar mass of FeF2, which is:

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So,

[tex]S = 8.4x10^{-3}x93.8

S = 0.788 g/L

4 0
3 years ago
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