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Rina8888 [55]
3 years ago
6

The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is

0.54 M? The rate constant for a first-order reaction is 0.54 s-1. What is the half-life of this reaction if the initial concentration is 0.54 M? 4.7 s 0.49 s 1.0 s 1.3 s 1.8 s
Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Answer:

The half life time of first order reaction is 1.3 sec

Explanation:

Given:

First order rate constant K = 0.54 M^{-1} s^{-1}

Initial concentration = 0.54 M

From the formula of first order half life time,

  K = \frac{0.693}{t_{\frac{1}{2} } }

So half life time is given by,

{t_{\frac{1}{y2} } } = \frac{0.693}{0.54}

{t_{\frac{1}{y2} } }  = 1.3 sec

Therefore, the half life time of first order reaction is 1.3 sec.

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What type of ions do nonmetals naturally form?
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You have a solution of 600 mg of caffeine dissolved in 100 mL of water. The partition coefficient for aqueous caffeine extracted
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Answer:

159 mg caffeine is being extracted in 60 mL dichloromethane

Explanation:

Given that:

mass of caffeine in 100 mL of water =  600 mg

Volume of the water = 100 mL

Partition co-efficient (K) = 4.6

mass of caffeine extracted = ??? (unknown)

The portion of the DCM = 60 mL

Partial co-efficient (K) = \frac{C_1}{C_2}

where; C_1= solubility of compound in the organic solvent and C_2 = solubility in aqueous water.

So; we can represent our data as:

K=(\frac{A_{(g)}}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL} )

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A+B = 60 mL

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A= 0.60 - B

4.6=(\frac{0.6-B(mg)}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL})

4.6 = \frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}

4.6 × (\frac{B_{(mg)}}{100mL}) = (\frac{0.6-B(mg)}{60mL} )

4.6 B *\frac{60}{100} = 0.6 - B

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2.76 + B = 0.6

3.76 B = 0.6

B = \frac{0.6}{3.76}

B = 0.159 g

B = 159 mg

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