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Vika [28.1K]
2 years ago
14

Why is cellulose not a source of nutrients for humans? Humans cannot absorb the hydrolyzed form of cellulose. Humans, and most v

ertebrates, lack the enzyme cellulase. Cellulose is a structural carbohydrate, and therefore is not useful as an energy source. Vertebrate enzymes hydrolyze (α 1–4) glucose linkages, but not glucose in the β configuration. Cellulose digestion must occur in a basic environment, but the human gut is acidic.
Chemistry
2 answers:
adell [148]2 years ago
8 0

Answer:

The correct answer is vertebrate enzyme hydrolyze alpha-1,4 glycosidic linkage but not glucose in the beta configuration.

Explanation:

The amylase that is present inside human body is called salivary alpha amylase,an enzyme that digest the alpha-1,4-glycosidic linkages of starch but does not act on those glycosidic linkages which are present in beta configuration.

       Cellulose contain beta-1,4-glycosidic linkages.That"s why it is not digested by the alpha amylase enzyme present inside the human body basically present in the saliva.

notsponge [240]2 years ago
8 0

"Humans" and most "vertebrates", lack the enzyme cellulose and "Vertebrate enzymes hydrolyze (a 1–4) glucose" linkages, but not glucose in the "ß configuration" these are the reasons is why cellulose is not the origin of nutrients for human beings.

Option: B and D

<u>Explanation</u>:

Cellulose is an example of polysaccharides (carbohydrate polymer linked with multiple glucose monosaccharide units). It is found in plants and breakdown of cellulose can only occur mainly in cows, buffaloes, horses, sheep, goats, termites etc as they have symbiotic bacteria in their intestinal tract which carry cellulose enzyme and responsible for cellulose hydrolysis in the gastro-intestinal tract. But animals cannot digest it 100% or directly. Cellulose is having glucose linked with beta acetal linkage which makes it alters from starch having alpha acetal linkage. Hence this mark reason behind the difference in digestibility of cellulose in animals and vertebrates.

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A red car and a blue car collide. What would be an example of Locard's exchange principle in this situation?
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Answer:

The blue car left paint on the red car

Explanation:

8 0
2 years ago
Four flasks are prepared, each containing 100mL of aqueous solutions of equal concentration. Which solution has the lowest freez
Jet001 [13]
The freezing point depression is a colligative property which means that it is proportional to the number of particles dissolved.

The number of particles dissolved depends on the dissociation constant of the solutes, when theyt are ionic substances.

If you have equal concentrations of two solutions on of which is of a ionic compound and the other not, then the ionic soluton will contain more particles (ions) and so its freezing point will decrease more (will be lower at end).   

In this way you can compare the freezing points of solutions of KCl, Ch3OH, Ba(OH)2, and CH3COOH, which have the same concentration.

As I explained the solution that produces more ions will exhibit the greates depression of the freezing point, leading to the lowest freezing point.

In this case, Ba(OH)2 will produce 3 iones, while KCl will produce 2, CH3OH will not dissociate into ions, and CH3COOH will have a low dissociation constant.

Answer: Then, you can predict that Ba(OH)2 solution has the lowest freezing point.
6 0
3 years ago
The Earth's asthenosphere is a structural layer made up on what?
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Gas is the answer ok
5 0
3 years ago
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The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.
user100 [1]

Answer:

c    43.38 g

Explanation:

The reaction  between MnO2 and HCl can be represented by the following balanced equation:

MnO2 + HCl ---> Cl2 + MnCl2 + H2O

From the balanced equation, the theoretically required molar ratio of MnO2 to HCl is 1:1, therefore the yields would have been expected to be equal.  

For the fact that HCl  gives a higher yield (65.02g) than MnO2 (60.25g) according to the problem statement, HCl should be in excess,  while the limiting reagent should be MnO2 .  

Thus, the theoretical yield of Cl2 will be  60.25 g.

By definition, the percentage yield is given by

% Yield = (Actual Yield) / (Theoretical Yield),  

This can be simplified to

Actual Yield = % Yield * Theoretical Yield

Plugging in the given values we have

Actual Yield = 72% *  60.25 = 43.38 g

5 0
3 years ago
1. If a solution containing 48.99 g of mercury(II) perchlorate is allowed to react completely with a solution containing 8.564 g
Vitek1552 [10]

1. Chemical eqn:

Hg(ClO4)2 + Na2S -> HgS + 2NaClO4

mercury perchlorate has a molar mass of 399.5g/mol (1d.p) and for Na2S it is 78.0g/mol (1d.p.)

no. of moles of mercury perchlorate= 48.99÷399.5= 0.12263mol(5s.f.)

no. of moles of Na2S= 8.564÷78.0= 0.10979mol ( 5s.f.)

so no. of moles of Hg(ClO4)2/ no. of moles of Na2S= 1/1 according to the eqn

so no. of moles of Hg(ClO4)2 needed if all Na2S is used up is 1/1×0.10979= 0.10979 mols

since no. of moles of mercury perchlorate needed < no. of moles of it provided, it is in excess and Na2S is the limiting factor.

since HgS is a solid and NaClO4 is aqueous, solid ppt formed will only be HgS.

no. of moles of HgS/ no. of moles of NaClO4= 1/1

no. of moles of HgS produced= 0.10979mols

molar mass of HgS= 232.7g/mol 1d.p.

grams of solid produced= 232.7×0.10979= 25.5g (3s.f.)

2. reactant in excess is Hg(ClO4)2,

no. of excess moles= 0.12263-0.10979= 0.01284mols

grams of excess reactant= 0.01284×399.5= 5.13g (3s.f.)

3 0
3 years ago
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