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Sunny_sXe [5.5K]
3 years ago
12

What is the role of the nervous system?

Chemistry
1 answer:
kap26 [50]3 years ago
8 0

Answer:

Explanation:

The major regulation, regulatory, and communicating system in the body is the nervous system. It is the foundation of all mental operation, including thinking, learning, and memory. The nervous system, along with the endocrine system, is responsible for controlling and sustaining homeostasis.

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Suppose that you lowered the temperature of a gas from 100˚C to 50 ˚C. By what factor do you change the volume of the gas?
Maru [420]

Answer:- Volume decreases by a factor of 1.15.

Solution:- At constant pressure, volume of the gas is directly proportional to the the kelvin temperature.

The equation is written as:

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where, V_1 is the volume at initial temperature T_1 and V_2 is the volume at final temperature T_2 .

Temperature must be in kelvins. So, let's convert both the temperatures to kelvin.

To convert degree C to kelvin we add 273.

So, T_1  = 100 + 273 = 373 K

T_2 = 50 + 273 = 323 K

The equation could also be written as:-

\frac{V_1}{V_2}=\frac{T_1}{T_2}

\frac{V_1}{V_2}=\frac{373}{323}

\frac{V_1}{V_2} = 1.15

From here we could say that the volume decreases by a factor of 1.15.

For example if the initial volume V_1 is 1 L then final volume V_2 will be \frac{1L}{1.15} that is 0.87 L.




4 0
3 years ago
How are changes in state related to thermal energy and particle motion​
frozen [14]

Answer:

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Explanation:

6 0
3 years ago
Has anyone done this???!!!
wlad13 [49]

Answer:

top one is anaphase and the middle one is cytokinesis can't see enough of the bottom one to tell

Explanation:

6 0
3 years ago
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What is the simple sugar resulting from the hydrolysis of lactose?
garri49 [273]

Glucose and galactose (both simple sugars) are produced from the hydrolysis of lactose.

5 0
4 years ago
Which of the following changes would have no effect on the equilibrium position of the reaction below? 2 NOBR (g) 2 NO (g)+ Br2
nasty-shy [4]

Answer:

D) cutting the concentrations of both NOBr and NO in half

Explanation:

The equilibrium reaction given in the question is as follows -

2NOBr ( g ) ↔  2NO ( g ) + Br₂ ( g )

The equilibrium constant for the above reaction can be written as -

K = [ NO ]² [ Br₂ ] / [ NOBr ] ²

Therefore from the condition given in the question , the changes that will not affect the equilibrium will be , reducing the concentration of both NOBr and NO to half ,

Hence ,

the new concentrations are as follows -

[ NoBr ] ' = 1/2 [ NoBr ]

[ NO ] ' = 1/2  [ NO ]

Hence the new equilibrium constant equation can be written as -

K ' = [ NO ] ' ² [ Br₂ ] / [ NOBr ]  ' ²

Substituting the new concentration terms ,

K ' = 1/2  [ NO ] ² [ Br₂ ] / 1/2 [ NoBr ]  ²

K ' = 1/4  [ NO ] ² [ Br₂ ] / 1/4 [ NoBr ]  ²

The value of 1 / 4 in the numerator and the denominator is cancelled -

K ' =   [ NO ] ² [ Br₂ ] /  [ NoBr ]  ²

Hence ,

K' = K

5 0
4 years ago
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