Answer:
Percentage error = 1.88 %
Solution:
Data Given:
Mass of Sample = 20.46 g
Volume of Sample = 43.0 mL - 40.0 mL = 3.0 mL
Formula Used:
Density = Mass / Volume
Putting values,
Density = 20.46 g / 3.0 mL
Density = 6.82 g.mL⁻¹
Percentage Error:
Experimental Value = 6.82 g.mL⁻¹
Accepted Value = 6.95 g.mL⁻¹
= 6.82 g.mL⁻¹ / 6.95 g.mL⁻¹ × 100 = 98.12 %
Percentage Error = 100 % - 98.12 %
Percentage error = 1.88 %
Answer:
See explanation
Explanation:
The reaction between alcohol and acidified potassium dichromate is a redox reaction. This reaction can be used to detect a drunken driver.
Alcohols can be oxidized to aldehydes, ketones and carboxylic acids depending on the structure of the alcohol. Primary alcohols yield adehydes and carboxylic acids while secondary alcohols are oxidized to ketones.
The colour of the acidified potassium dichromate turns from orange to green when exposed to alcohols from the breath of a drunken driver.
Substances that exist in solution almost completely as ions are called strong electrolytes. Therefore, the answer is C.
<h3><u>Answer</u>;</h3>
19 mg
<h3><u>Explanation</u>;</h3>
dose = 5.0 mg/kg
weight of infant = 8.5 pounds
Convert 8.5 pounds to kg: 8.5 pounds = 3.86 kg
Therefore;
The dose to give the infant is:
= (5.0 mg/kg) x (3.86 kg)
= 19.3 mg
<u>≈ 19 mg</u>