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baherus [9]
3 years ago
11

How many grams of oxygen are in 5.3 moles of lactose? (Using percent composition)

Chemistry
1 answer:
Misha Larkins [42]3 years ago
8 0
Hey Umm here you can search it honey bun
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Pls pls I need help to solve this questions
cupoosta [38]
1) • Solubility is the ability of a substance to be dissolved especially in water
• Unit; mg/L (milligrams per liter)

2) A saturated solution is a chemical solution containing the maximum concentration of a solute dissolved in the solvent.

3) To detoxify any acid that was previously used in it

4) CAN’T SEE THE MAIN QUESTIONS

5) CAN’T SEE THE MAIN QUESTIONS
6 0
4 years ago
1.As you move from left to right across a period,the number of valence electrons
never [62]
1. it increases then decreases i.e +1, +2, +3, +4, +5, -2, -1 then 0.
2. group 6 elements have more valence electrons than group 2.
3.fluorine is the most reactive because reactivity and electronegativity reduces down the group.
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5 0
3 years ago
It refers to the cracked sections of the earth's crust.
poizon [28]

Answer:

Plates

Explanation:

The Earth's crust is broken up into sections called plates. Tectonic plates are on the mantle which allow them to move.

4 0
3 years ago
Read 2 more answers
12. Organelles allow eukaryotic cells to carry out more functions than prokaryotic cells.
deff fn [24]

Answer:

True po

Explaination :

I hope it helps

4 0
3 years ago
Read 2 more answers
A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150
Usimov [2.4K]

Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

M=\frac{Moles of substance X}{Volume of the solution}

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}

Then you can solve for the volume of the solution:

Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL

Hope it helps!

3 0
4 years ago
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