Answer:
Females = 17 and males = 23
Step-by-step explanation:
Given that,
Total no of students in the class = 40
Let no. of females = x
No. of males = 6+x
ATQ,
Total students = males + females
40 = x+6+x
40-6 = 2x
34 = 2x
x = 17
Hence, there are 17 females and (6+17= 23) males.
Remark
If the lines are parallel then triangle RQS will be similar to triangle RTP
From that, all three lines in one triangle will bear the same ratio to all three lines of the second triangle.
Givens
PQ = 8
QR = 5
RS = 15
ST = x + 3
Ratio
QR/RP = RS/RT
Sub and solve
RP = 5 + 8
RP = 13
RT = 15 + x + 3
RT = 18 + x
5/13 = 15 / (18 + x) Cross multiply
5(18 + x) = 195 Remove the brackets on the left.
90 + 5x = 195 Subtract 90 from both sides.
5x = 105 Divide by 5
x = 105/5
x = 21 Answer <<<<<<<
Probabilities are used to determine the chances of events
The probability that Jill selects a wooden pencil and then a mechanical pencil is 8%
<h3>How to calculate the probability</h3>
Represent the events as follows:
- A represents mechanical pencil
- B represents wooden pencil
- C represents colored pencil
So, we have
P(A) = 20%
P(B) = 40%
P(C) = 30%
The probability that Jill selects a wooden pencil and then a mechanical pencil is then calculated as:
P(B n A) = P(B) * P(A)
This gives
P(B n A) = 40% * 20%
Evaluate the product
P(B n A) = 8%
Hence, the probability that Jill selects a wooden pencil and then a mechanical pencil is 8%
Read more about probabilities at:
brainly.com/question/9385303
Answers:
Vertical asymptote: x = 0
Horizontal asymptote: None
Slant asymptote: (1/3)x - 4
<u>Explanation:</u>
d(x) = 
= 
Discontinuities: (terms that cancel out from numerator and denominator):
Nothing cancels so there are NO discontinuities.
Vertical asymptote (denominator cannot equal zero):
3x ≠ 0
<u>÷3</u> <u>÷3 </u>
x ≠ 0
So asymptote is to be drawn at x = 0
Horizontal asymptote (evaluate degree of numerator and denominator):
degree of numerator (2) > degree of denominator (1)
so there is NO horizontal asymptote but slant (oblique) must be calculated.
Slant (Oblique) Asymptote (divide numerator by denominator):
- <u>(1/3)x - 4 </u>
- 3x) x² - 12x + 20
- <u>x² </u>
- -12x
- <u>-12x </u>
- 20 (stop! because there is no "x")
So, slant asymptote is to be drawn at (1/3)x - 4
