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statuscvo [17]
2 years ago
15

( i will give brainlist ) What is the equation of the following graph?

Mathematics
1 answer:
Ne4ueva [31]2 years ago
7 0

Answer:

y= ⅓x +2

Step-by-step explanation:

Since the graph is a linear graph, let's use the slope-intercept form to find its equation.

<u>Slope-intercept </u><u>form</u>

y= mx +c, where m is the slope and c is the y-intercept.

The y-intercept is the point at which the graph cuts through the y-axis. In this case, the y-intercept is 2.

Thus, y= mx +2.

Let's find the slope of the graph.

First, identify 2 pairs of coordinates from the graph:

(0, 2) and (3, 3)

Next, substitute these coordinates into the slope formula below:

\boxed{ \text{slope} = \frac{y _{1} - y_2 }{x_1 - x_2} }

slope

=  \frac{3 - 2}{3 - 0}

=  \frac{1}{3}

Thus, the equation of the graph is y= ⅓x +2.

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Natasha_Volkova [10]
Hi there!

First, let's use a proportion to figure out the commission the salesperson makes. 

WORK:
x/15486 = 3/100
100x = 46458
x = 464.58 (commission)

Next, we'll add together the commission and her salary.

WORK:
464.58 + 1200 = 1664.58

ANSWER:
$1664.58


Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
5 0
3 years ago
Please don’t judge me please if I don’t know
vladimir2022 [97]

Answer:

its ok

Step-by-step explanation:

there is this app called photo math where you take a picture of the problem and its answers you but the answer is -4g

8 0
3 years ago
Find all solutions to the equation. -\dfrac{2}{x(x+2)}=\dfrac{x+3}{x+2}− x(x+2) 2 ​ = x+2 x+3 ​ minus, start fraction, 2, divide
Gnoma [55]

Answer:

x=-1

Step-by-step explanation:

We have been given an equation \frac{-2}{x(x+2)}=\frac{x+3}{x+2}. We are asked to find the solutions of our given equation.

First of all, we will cross multiply our given equation as:

-2(x+2)=x(x+2)(x+3)

Subtract x(x+2)(x+3) from both sides:

-2(x+2)-x(x+2)(x+3)=x(x+2)(x+3)-x(x+2)(x+3)

-2(x+2)-x(x+2)(x+3)=0

Now we will factor out (x+2).

(x+2)(-2-x(x+3))=0

(x+2)(-2-x^2-3x)=0

(x+2)(-(x^2+3x+2))=0

Now we will factor by splitting the middle term.

-(x+2)(x^2+2x+x+2)=0

-(x+2)(x+2)(x+1)=0

-(x+2)^2(x+1)=0

Now we will use zero product property and solve for x as:

-(x+2)^2=0,(x+1)=0

(x+2)=0,(x+1)=0

x=-2,x=-1

Now, we will check for extraneous solutions.

We can see that x=-2 will make both denominators zero because our function is not defined at  x=-2.

Therefore, the solution for our given equation is x=-1.

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4 years ago
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