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dem82 [27]
2 years ago
10

Meteorologists are interested in the relationship between minimum pressure and maximum wind speed

Physics
1 answer:
pogonyaev2 years ago
7 0

Meteorologists are curious about the association between hurricane minimum pressure and maximum wind speed.

<h3>Who is meteorologist?</h3>

A meteorologist is one who studies and works in the discipline of meteorology with the goal of understandings weather.

Meteorologists are curious about the association between hurricane minimum pressure and maximum wind speed.

From 1995 through 2012, the lowest pressure in millibars and maximum wind speed in knots were gathered for a random sample of 100 storms.

Hence,meteorologists are curious about the association between hurricane minimum pressure and maximum wind speed.

To learn more about the meteorologist, refer:

brainly.com/question/5145125

#SPJ4

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Answer:

Professional education as a science has been defined as a field of educational science that studies the growth of a person into a profession and the related problems. It refers to organized education aimed at the knowledge and skills needed in the profession and working life, as well as growing into active citizenship and membership of society. Professional education as a discipline studies vocational training, skills and learning related to the profession and working life.  

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7 0
3 years ago
A 1.40-kg ball tied to a string fixed to the ceiling is pulled to one side by a force F→ . where L = 1.40 kg. What is the tensio
riadik2000 [5.3K]

Answer:

T=13.72N

Explanation:

The tension before the ball is released have no angle is in rest at the same axis of the weight so:

∑F=0

Using Newton law in this case the ball is tied so tension before become to swing is

∑F=FN-T=0

T=F_{N}

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8 0
3 years ago
A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 781 K, and r
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Answer:2.517 J/K

Explanation:

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thus change in Entropy is given by \frac{\sum Q}{T}

\Delta S=\frac{\sum Q}{T}=-\frac{Q}{T_1}+\frac{Q}{T_2}

\Delta S=\frac{\sum Q}{T}=-\frac{1477}{781}+\frac{1477}{335}

\Delta S=\frac{\sum Q}{T}=-1.891+4.4089

\Delta S=\frac{\sum Q}{T}=2.517 J/K                              

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