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3 years ago

A hunter who is standing 220.0-m away fires his rifle. How long (in seconds) will it take the sound to travel to your ear.

Physics

1 answer:

natta225 [31]3 years ago

6 0

Answer:

t = 1.52 s

Explanation:

The speed of sound is constant and depends only on the properties of the medium in which the sound propagates, many of these properties change with temperature, in the case of propagation in air, the speed of sound

v = $331 \ \sqrt{1+ \frac{T}{273} }$

where the temperature is in degrees centigrade

v = 331 $\sqrt{1+ \frac{6}{273} }$ = 331 1.0109

v = 334.6 m / s

let's use the uniform motion relationships

v = x / t

t = v / x

let's calculate

t = 334.6 / 220.0

t = 1.52 s

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Which quantity is a vector quantity A. Acceleration B. Mass C. Speed D. Volume

Marianna [84]

Answer:

Acceleration

Explanation:

A vector quantity has a magnitude and direction. Mass, Speed and Volume are all scalar quantities because they only have magnitude, and not direction.

5 0

3 years ago

The basic barometer can be used to measure the height of a building. If the barometric readings at the top and the bottom of a b

erma4kov [3.2K]

Answer:

$h = 269.6 m$

Explanation:

Pressure at the bottom of the building and at the top of the building must be related as

$P_{top} = P_{bottom} - \rho g h$

$P_{top} = 730 mm Hg$

$P_{bottom} = 755 mm Hg$

now we will have

$(755 \times 10^{-3})(13.6 \times 10^3)(9.81) = P_{bottom}$

$P_{bottom} = 1.007 \times 10^5 Pa$

$P_{top} = (730\times 10^{-3})(13.6 \times 10^3)(9.81)$

$P_{top} = 0.974 \times 10^5$

now we have

$(1.007 - 0.974)\times 10^5 = 1.25 (9.81) h$

$h = 269.6 m$

7 0

3 years ago

A body of mass 2 kg at O has an initial velocity of 3m/s along OE and it is subjected to a force of 4N perpendicular to OE the d

timofeeve [1]

Perpendicular acceleration:
F = ma
a = 4 / 2 = 2 m/s²

Perpendicular distance:

s = ut + 1/2 at²
s = 0 x 4 + 1/2 x 2 x 4²
s = 16 m

Horizontal distance:
s = ut
= 3 x 4
= 12 m

Total distance = √(12² + 16²)
= 20 m.

3 0

3 years ago

What happens when magma rises towards the surface?

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3 years ago

Read 2 more answers

A student throws a baseball horizontally at 25 meters per second from a cliff 45 meters above the level ground. Approximately ho

Delicious77 [7]

First, calculate how long the ball is in midair. This will depend only on the vertical displacement; once the ball hits the ground, projectile motion is over. Since the ball is thrown horizontally, it originally has no vertical speed.
t = time vi = initial vertical speed = 0m/s g = gravity = -9.8m/s^2 y = vertical displacement = -45m
y = .5gt^2 [Basically, in this equation we see how long it takes the ball to fall 45m] -45m = .5 (-9.8m/s^2) * t^2 t = 3.03 s
Now we know that the ball is midair for 3.03s. Since horizontal speed is constant we can simply use:
x = horizontal displacement v = horizontal speed = 25m/s t = time = 3.03s
x = v*t x = 25m/s * 3.03s = 75.76 m Thus, the ball goes about 75 or 76 m from the base of the cliff.

8 0

4 years ago