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JulsSmile [24]
3 years ago
13

A hunter who is standing 220.0-m away fires his rifle. How long (in seconds) will it take the sound to travel to your ear.

Physics
1 answer:
natta225 [31]3 years ago
6 0

Answer:

t = 1.52 s

Explanation:

The speed of sound is constant and depends only on the properties of the medium in which the sound propagates, many of these properties change with temperature, in the case of propagation in air, the speed of sound

          v =331 \ \sqrt{1+ \frac{T}{273} }

where the temperature is in degrees centigrade

         v = 331 \sqrt{1+ \frac{6}{273} } = 331    1.0109

         v = 334.6 m / s

let's use the uniform motion relationships

         v = x / t

          t = v / x

let's calculate

          t = 334.6 / 220.0

          t = 1.52 s

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Read 2 more answers
A spring stretches by 0.0208 m when a 3.39-kg object is suspended from its end. How much mass should be attached to this spring
sashaice [31]

Answer:

COMPLETE QUESTION

A spring stretches by 0.018 m when a 2.8-kg object is suspended from its end. How much mass should be attached to this spring so that its frequency of vibration is f = 3.0 Hz?

Explanation:

Given that,

Extension of spring

x = 0.0208m

Mass attached m = 3.39kg

Additional mass to have a frequency f

Let the additional mass be m

Using Hooke's law

F= kx

Where F = W = mg = 3.39 ×9.81

F = 33.26N

Then,

F = kx

k = F/x

k = 33.26/0.0208

k = 1598.84 N/m

The frequency is given as

f = ½π√k/m

Make m subject of formula

f² = ¼π² •(k/m

4π²f² = k/m

Then, m4π²f² = k

So, m = k/(4π²f²)

So, this is the general formula,

Then let use the frequency above

f = 3Hz

m = 1598.84/(4×π²×3²)

m = 4.5 kg

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