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IgorLugansk [536]
3 years ago
13

What is the first step of the hydrogen fusion process?

Physics
2 answers:
Slav-nsk [51]3 years ago
8 0
The first step is the fusion of hydrogen into Deuterium.
kirill115 [55]3 years ago
5 0
The first step is Deuterium
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Jen pushed a box for a distance of 80m with 20 N of force. How much work did she do?
Drupady [299]
The answer is 1,600 J.

A work (W) can be expressed as a product of a force (F) and a distance (d):
W = F · d<span>

We have:
W = ?
F = 20 N = 20 kg*m/s</span>²
d = 80 m
_____
W = 20 kg*m/s² * 80 m
W = 20 * 80 kg*m/s² * m
W = 1600 kg*m²/s²
W = 1600 J
8 0
3 years ago
A 10 kilogram lump of rock weighs 16N on the Moon.
qwelly [4]

Answer:

c

Explanation:

it's the only one that makes sense

4 0
2 years ago
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Plsss hlppppppp!!!!!!!!!!!!!
masya89 [10]

Explanation:

The angular momentum is doubled because it is proportional to the angular velocity.

6 0
2 years ago
Suppose that a rectangular toroid has 1,500 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i
V125BC [204]

Answer:

Current in the toroid will be I=17.32\times 10^{-3}A

Explanation:

We have given number of winding in rectangular toroid N = 1500

Self inductance of toroid L = 0.06 H

Magnetic energy stored in toroid E=9\times 10^{-16}J

We have to find the current in the toroid

Magnetic energy stored is equal to E=\frac{1}{2}Li^2

9\times 10^{-6}=\frac{1}{2}\times 0.06\times I^2

I=17.32\times 10^{-3}A

So current in the toroid will be I=17.32\times 10^{-3}A

5 0
4 years ago
(4%) Problem 9: A mass is connected to a spring and is allowed to move horizontally. The mass is at a position L when the spring
skad [1K]

Answer:

a) Acceleration is zero , c)   Speed ​​is cero

Explanation:

a) the equation that governs the simple harmonic motion is

         x = A cos (wt +φφ)

Where A is the amplitude of the movement, w is the angular velocity and φ the initial phase determined by the initial condition

Body acceleration is

         a = d²x / dt²

Let's look for the derivatives

         dx / dt = - A w sin (wt + φ)

         a = d²x / dt² = - A w² cos (wt + φ)

In the instant when it is not stretched x = 0

As the spring is released at maximum elongation, φ = 0

            0 = A cos wt

            Cos wt = 0         wt = π / 2

Acceleration is valid for this angle

           a = -A w² cos π/2 = 0

Acceleration is zero

b)

c) When the spring is compressed x = A

Speed ​​is

             v = dx / dt

             v = - A w sin wt

We look for time

            A = A cos wt

            cos wt = 1         wt = 0, π

For this time the speedy vouchers

            v = -A w sin 0 = 0

Speed ​​is cero

5 0
3 years ago
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