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Artist 52 [7]
2 years ago
14

Please help on this mathematical problem

Mathematics
2 answers:
trapecia [35]2 years ago
7 0

8.5 percent of people between 35 and 54 prefer football.

adell [148]2 years ago
5 0

Answer:

37%

Step-by-step explanation:

There are 27 people between the age of 35 and 54. Of these people, 10 prefer football. To find the percentage, you divide the number of people in the age group who prefer football by the total number of people in the age group.

10/27 = .37037...

or 37.04%

Since it asks for the nearest whole number, 37% of people aged 35-54 prefer football.

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The cost for fudge at Sweet Treats is represented by y = 4x, where y is the price paid in dollars for x pounds. The table shows
NikAS [45]

Answer:

A. $16 Dollars

Step-by-step explanation:

4 0
3 years ago
One hundred coins weigh 346 grams. How many grams does 1 coin weigh?
Pani-rosa [81]

Answer:

3.46 grams

Step-by-step explanation:

346/100 - 3.46

3 0
3 years ago
Find the GCF of 6,36
Ksju [112]

Answer:

Okay, so the answer would be 6. please let this be the brainliest.

Step-by-step explanation:

Find the prime factorization of 36

36=2x2x3x3

gcf-2x3

7 0
3 years ago
Suppose a computer manufacturer has the total cost function
S_A_V [24]

Answer:

(a)  P(x) = 300 x - 3600

(b)  P(340) = $ 98400

(c)  At least 12 items must be sold to avoid losing money.

Step-by-step explanation:

Part (a):

The Profit function is the difference between the revenue function (R(x)) and the Cost (C(x)) function:

P(x) = R(x) - C(x)

P(x) = 384 x - [84 x + 3600]

P(x) = 384 x - 84 x - 3600

P(x) = 300 x - 3600

Part (b):

The profit on 340 items is:

P(340) = 300 (340) - 3600

P(340) = 102000 - 3600

P(340) = $ 98400

Part (c):

To avoid losing money, the profit P(x) has to be larger or equal than zero. That is:

P(x) \geq 0

300 x -3600  \geq 0

300 x  \geq 3600

x  \geq 3600/300

x  \geq 12

So at least 12 items must be sold to avoid losing money.

7 0
2 years ago
A data set includes weights of garbage discarded in one week from 62 different households. The paired weights of paper and glass
lara [203]

Answer:

Because the absolute value of the test statistic is <u>less than</u> the positive critical value, there <u>is not</u> enough evidence to support the claim that there is a linear correlation between the weights of discarded paper and glass for a significance level of α = 0.05.

Step-by-step explanation:

The correlation​ matrix provided is:

Variables    Paper     Glass

  Paper           1         0.1853

 Glass        0.1853         1

Te hypothesis for the test is:

<em>H</em>₀: <em>ρ</em> = 0 vs. <em>H</em>₀: <em>ρ</em> ≠ 0

The test statistic is:

<em>r</em> = 0.1853 ≈ 0.185

As the alternate hypothesis does not specifies the direction of the test, the test is two tailed.

The critical value for the two-tailed test is:

r_{\alpha/2, (n-2)}=r_{0.05/2, (62-2)}=r_{0.05/2, 60}=0.250

The conclusion is:

Because the absolute value of the test statistic is <u>less than</u> the positive critical value, there <u>is not</u> enough evidence to support the claim that there is a linear correlation between the weights of discarded paper and glass for a significance level of α = 0.05.

6 0
3 years ago
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