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kenny6666 [7]
4 years ago
5

For two events and , the probability that occurs is 0.8, the probability that occurs is 0.4, and the probability that both occur

s is 0.2. Given that occurred, what is the probability that also occurred?
Mathematics
1 answer:
sergey [27]4 years ago
7 0

Answer:

P(B|A)=0.25  , P(A|B) =0.5

Step-by-step explanation:

The question provides the following data:

P(A)= 0.8

P(B)= 0.4

P(A∩B) = 0.2

Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.

To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:

P(B|A) = P(A∩B)/P(A)

      = (0.2) / (0.8)  

P(B|A)=0.25

To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:

P(A|B) = P(A∩B)/P(B)

          = (0.2)/(0.4)

P(A|B) =0.5

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Mandy divided the sum of 12 and
Aleksandr [31]

Answer:

35

Step-by-step explanation:

I hope this helps you.

12+24=38

38÷6=31

31+4=35

4 0
3 years ago
Help, I don't remember​
GenaCL600 [577]

Answer:

  x = 144

Step-by-step explanation:

What you need to remember about this geometry is that all of the triangles are similar. As with any similar triangles, that means ratios of corresponding sides are proportional. Here, we can write the ratios of the long leg to the short leg and set them equal to find x.

  x/60 = 60/25

Multiply by 60 to find x:

  x = (60·60)/25

  x = 144

_____

<em>Comment on this geometry</em>

You may have noticed that the above equation can be written in the form ...

  60 = √(25x)

That is, the altitude from the hypotenuse (60) is equal to the geometric mean of the lengths into which it divides the hypotenuse (25 and x).

This same sort of "geometric mean" relation holds for other parts of this geometry, as well. The short leg of the largest triangle (the hypotenuse of the one with legs 25 and 60) is the geometric mean of the short hypotenuse segment (25) and the total hypotenuse (25+x).

And, the long leg of the large triangle (the hypotenuse of the one with legs 60 and x) is the geometric mean of the long hypotenuse segment (x) and the total hypotenuse (25+x).

While it can be a shortcut in some problems to remember these geometric mean relationships, you can always come up with what you need by simply remembering that the triangles are all similar.

3 0
3 years ago
Test is worth 50 points; test score of 84% idk
aleksklad [387]
84% of 50 is 42. So if your test was graded out of 50 you would've gotten 42/50. If you multiply 50 by 2 (50x2), you have 100, so then you'd just divide the 84% by 2 so you'd get 42%
6 0
3 years ago
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Figure ABCD is transformed to figure A prime B prime C prime D prime, as shown: A coordinate grid is shown from negative 5 to 0
Bess [88]

Answer:

i need this answer too

7 0
3 years ago
(k^2-6k^4)-(3k^4+k^2+2)
jeka57 [31]

Step-by-step explanation:

Vamos simplificar passo a passo.

k2-6k4-(3k4+k2+2)

Distribua o sinal negativo:

=k2-6k4+-1(3k4+k2+2)

=k2+-6k4+-1(3k4)+-1k2+(-1)(2)

=k2+-6k4+-3k4+-k2+-2

Combine os termos semelhantes:

=k2+-6k4+-3k4+-k2+-2

=(-6k4+-3k4)+(k2+-k2)+(-2)

=-9k4+-2

Responda:

=-9k4-2

7 0
3 years ago
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