Answer:
A mass is suspended on a spring. The spring is compressed so that the mass is located 5 cm above its rest position. The mass is released at time t = 0 and allowed to oscillate. It is observed that the mass reaches its lowest points after it is released. Find an equation that describes the motion of the mass.
1/2
Explanation:
We do not start at y=0y=0 so it is better to use a cosine curve. The hanging string is compressed to a position that is y=5y=5 units above the rest position. Hence, |a|=5∣a∣=5. Also, since we begin at positive values, then a=5a=5.
We begin at the highest point y=5y=5.
Please vote me as brainliest
Answer:
The time taken is ![t = 0.4103 \ s](https://tex.z-dn.net/?f=t%20%3D%200.4103%20%5C%20s)
Explanation:
From the question we are told that
The speed is ![v = 130 \ mi/h = 58 \ m/s](https://tex.z-dn.net/?f=v%20%20%3D%20%20130%20%5C%20%20mi%2Fh%20%3D%20%2058%20%5C%20%20m%2Fs)
The length of the tennis court ![l = 78 \ ft = \frac{78}{3.281}= 23.8 \ m](https://tex.z-dn.net/?f=l%20%3D%20%2078%20%5C%20ft%20%3D%20%5Cfrac%7B78%7D%7B3.281%7D%3D%2023.8%20%5C%20m)
Generally the time taken is mathematically represented as
![t = \frac{ 23.8}{ 58}](https://tex.z-dn.net/?f=t%20%3D%20%20%5Cfrac%7B%2023.8%7D%7B%2058%7D)
=> ![t = 0.4103 \ s](https://tex.z-dn.net/?f=t%20%3D%200.4103%20%5C%20s)
a) 0.26 h
b) 71.4 km
Explanation:
a)
In order to solve the problem, we have to know what is the final velocity of the car.
Here, we assume that the final velocity reached by the car is
![v=300 km/h](https://tex.z-dn.net/?f=v%3D300%20km%2Fh)
Therefore, we can find the time taken by the car to reach this velocity by using the suvat equation:
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
where:
u = 250 km/h is the initial velocity
is the acceleration of the car
v = 300 km/h is the final velocity
t is the time
Solving for t, we find:
![t=\frac{v-u}{a}=\frac{300-250}{190}=0.26 h](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bv-u%7D%7Ba%7D%3D%5Cfrac%7B300-250%7D%7B190%7D%3D0.26%20h)
b)
In order to find the distance covered by the car, we can use the following suvat equation:
![s=ut+\frac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2)
where:
s is the distance covered
u is the initial velocity
a is the acceleration
t is the time
For the car in this problem, we have:
u = 250 km/h
t = 0.26 h (calculated in part a)
![a=190 km/h^2](https://tex.z-dn.net/?f=a%3D190%20km%2Fh%5E2)
Therefore, the distance covered is
![s=(250)(0.26)+\frac{1}{2}(190)(0.26)^2=71.4 km](https://tex.z-dn.net/?f=s%3D%28250%29%280.26%29%2B%5Cfrac%7B1%7D%7B2%7D%28190%29%280.26%29%5E2%3D71.4%20km)
Answer:
a. abyssal plain far from a continent
Explanation:
- The sediments of the abyssal plains contain of the abundant mineral resources and notably polymetallic nodules and re also called the manganese nodules and these are on the shape of potatoes and distributed at the depths of about 4000 meters.
- <u>And they lie at the international line of the pacific oceans stretching in an area of 118°–157°, and from 9°–16°N, that is 3 million m square is currently under the noddle exploration and discovery.</u>