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abruzzese [7]
3 years ago
14

An object is thrown directly up (positive direction) with a velocity (v o ) of 20.0 m/s and d o = 0. How high does it rise (v =

0 cm/s at top of rise). Remember, acceleration is -9.80 m/s^2 .
Physics
1 answer:
Lelechka [254]3 years ago
5 0

Answer:

h=20.38 m

Explanation:

Given that

Initial speed of object u = 20 m/s

Acceleration  g= 9.8\ \frac{m}{s^2}

We know that

v^2=u^2-2gh

Here acceleration and velocity is in opposite direction so the object will come rest after reaching at distance h.When body will reach at its highest position then velocity will become zero(v=0).

Now by putting the values

v^2=u^2-2gh

0 =20^2-2\times 9.1\times h

h=20.38 m

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Vitamins and iron are nutrients that provide energy to the human body.<br> A true<br> B false
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A disk with radius R and uniform positive charge density s lies horizontally on a tabletop. A small plastic sphere with mass M a
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Answer:

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So, the net force on the small plastic sphere of mass M and charge Q is

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F = Qs/2ε₀[1 - z/√(z² + R²)]

b. At what height h does the sphere hover?

The sphere hovers at height z = h when the electric force equals the weight of the sphere.

So, F = mg

Qs/2ε₀[1 - z/√(z² + R²)] = mg

when z = h, we have

Qs/2ε₀[1 - h/√(h² + R²)] = mg

[1 - h/√(h² + R²)] = 2mgε₀/Qs

h/√(h² + R²) = 1 - 2mgε₀/Qs

squaring both sides, we have

[h/√(h² + R²)]² = (1 - 2mgε₀/Qs)²

h²/(h² + R²) = (1 - 2mgε₀/Qs)²

cross-multiplying, we have

h² = (1 - 2mgε₀/Qs)²(h² + R²)

expanding the bracket, we have

h² = (1 - 2mgε₀/Qs)²h² + (1 - 2mgε₀/Qs)²R²

collecting like terms, we have

h² - (1 - 2mgε₀/Qs)²h² = (1 - 2mgε₀/Qs)²R²

Factorizing, we have

[1 - (1 - 2mgε₀/Qs)²]h² = (1 - 2mgε₀/Qs)²R²

So, h² =  (1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]

taking square-root of both sides, we have

√h² =  √[(1 - 2mgε₀/Qs)²R²/[1 - (1 - 2mgε₀/Qs)²]]

h =  (1 - 2mgε₀/Qs)R/√[1 - (1 - 2mgε₀/Qs)²]

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Now, if you look at the image, you can see a triangle rectangle.

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sin(θ) = 3m/5m

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then the vector is:

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pogonyaev

Answer: The volume of an irregularly shaped object is 0.50 ml

Explanation:

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