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3 years ago

14

An object is thrown directly up (positive direction) with a velocity (v o ) of 20.0 m/s and d o = 0. How high does it rise (v =

0 cm/s at top of rise). Remember, acceleration is -9.80 m/s^2 .

1 answer:

Lelechka [254]3 years ago

5 0

Answer:

h=20.38 m

Explanation:

Given that

Initial speed of object u = 20 m/s

Acceleration $g= 9.8\ \frac{m}{s^2}$

We know that

$v^2=u^2-2gh$

Here acceleration and velocity is in opposite direction so the object will come rest after reaching at distance h.When body will reach at its highest position then velocity will become zero(v=0).

Now by putting the values

$v^2=u^2-2gh$

$0 =20^2-2\times 9.1\times h$

h=20.38 m

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$\rho$ - Densidad del agua, en kilogramos por metro cúbico.

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La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.

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Si sabemos que $v\approx 1469,694\,\frac{m}{s}$ y $f = 1000\,hz$ , entonces la longitud de onda de las ondas sonoras es:

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La longitud de onda de las ondas sonoras es 1,470 metros.

Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: brainly.com/question/1070238

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bagirrra123 [75]

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This must be the answer since the return time is known. If you want to delete this time

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