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abruzzese [7]
3 years ago
14

An object is thrown directly up (positive direction) with a velocity (v o ) of 20.0 m/s and d o = 0. How high does it rise (v =

0 cm/s at top of rise). Remember, acceleration is -9.80 m/s^2 .
Physics
1 answer:
Lelechka [254]3 years ago
5 0

Answer:

h=20.38 m

Explanation:

Given that

Initial speed of object u = 20 m/s

Acceleration  g= 9.8\ \frac{m}{s^2}

We know that

v^2=u^2-2gh

Here acceleration and velocity is in opposite direction so the object will come rest after reaching at distance h.When body will reach at its highest position then velocity will become zero(v=0).

Now by putting the values

v^2=u^2-2gh

0 =20^2-2\times 9.1\times h

h=20.38 m

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In convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object .

<h2 /><h2>a) Position of the soda bottle (the object) </h2><h2 />

The Mirror equation is:

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}   (1)

Where:

f is the focal distance

u is the distance between the object and the mirror  

v is the distance between the image and the mirror

 

We already know the values of f and v, let's find u from (1):

u=\frac{v.f}{v-f}   (2)

Taking into account the explanation at the beginign of this asnswer:

f=-34cm and v=-18cm

The <u>negative signs</u> indicate the <u>focal distance</u> and the <u>distance between the image and the mirror are virtual </u>

Then:

u=\frac{(-18cm)(-34cm)}{-18cm-(-34cm)}  

u=38.25cm (3) >>>>Position of the soda bottle

<h2>b) magnification of the image </h2><h2 />

The magnification m of the image is given by:

m=-\frac{v}{u} (4)

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<h2>c) Describe the image </h2><h2 />

According to the explanations and results obtained in the prior answers, the correct option is 9:

<h2>The image is <u>virtual, upright, smaller</u> than the object </h2><h2 /><h2>d) Height of the soda bottle (object) </h2>

Another way to find the magnification is by the following formula:

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h_{i} is the image height

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We already know the values of m and h_{i}, let's find h_{o}:

h_{o}=\frac{h_{i}}{m} (7)

h_{o}=\frac{6.8cm}{0.47}  

h_{o}=14.46cm (8) >>>height of thesoda bottle

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