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Colt1911 [192]
3 years ago
11

If the net force acting on an object increases by 50 percent, then the acceleration of the object will

Physics
1 answer:
ki77a [65]3 years ago
8 0
<span>If the net force acting on an object increases by 50 percent, then
the acceleration of the object will also increase by 50 percent.

This answer is not offered among the list of choices.

So the correct response is "D. none of the above"</span>
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A good way to demagnitize something
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Answer:

heat it up to above 176f or apply alternating current

Explanation:

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3 years ago
What is the name of the process in which oceanic crust moves apart at mid-ocean ridges due to convention currents in the mantle?
Katena32 [7]
The answer is D seafloor spreading
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An airplane, starting from rest, moves down the runway at constant acceleration for 18 s and then takes off at a speed of 60 m/s
ruslelena [56]

Answer:

a =3.33 m/s²

Explanation:

given,

initial speed of Plane, u = 0 m/s

final speed of plane, v = 60 m/s

time of the acceleration, t = 18 s

average acceleration of the plane, a = ?

average acceleration is equal to change in velocity per unit time.

a = \dfrac{v - u}{t}

a = \dfrac{60 - 0}{18}

a = \dfrac{60}{18}

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Hence, average acceleration of the plane is equal to a =3.33 m/s²

4 0
3 years ago
Read 2 more answers
Why doesn’t the ball roll on forever after being kicked at a soccer game?
gavmur [86]

My guess would be because the gravity from the Earth's core is constantly pulling the ball towards the ground. It's like the moon. Why doesn't the moon just float away in space? Because Earth's gravitational pull keeps it rotating around it. Therefore, the ball will always be pulled towards the core which keeps it from from rolling forever due to friction. But i may be wrong, even though this a quite a good answer, hope it is right!

7 0
4 years ago
An astronomer at the equator measures the Doppler shift of sunlight at sunset. From this, she calculates that Earth's tangential
Ksivusya [100]

Answer : Radius of Earth is 6,340 Km.

Explanation

It is given that,

Tangential velocity of Earth at the equator, v = 465 m/s

Centripetal acceleration at the equation is, a_c=3.41\times 10^{-2}\ m/s^2

We know that the relation between centripetal acceleration and tangential velocity is :

a_c=\dfrac{v^2}{r}..........(1)

Where,

v is tangential velocity

r is the radius

Putting all values in equation (1)

3.41\times 10^{-2}\ m/s^2=\dfrac{(465 m/s)^2}{r}

r=6340909\ m

or

r=6,340\ Km

The Earth's radius is 6,340 Km. Hence, this is the required solution.

7 0
3 years ago
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