Part a)
As we know that energy stored inside the capacitor is given as
for a given capacitor we know
Now we can use it in above equation to find the energy
PART b)
If two negative charges are hold near to each other and then released
Then due to mutual repulsion they start moving away from each other
Due to mutual repulsion as the two charges moving away the electrostatic potential energy of two charges will convert into kinetic energy of the two charges.
So here as they move apart kinetic energy will increase while potential energy will decrease
Part c)
As we know that capacitance is given as
here we know that
Answer:
Low-temperature blackbody
Explanation:
There are 3 types of blackbody temperatures.
Low-temperature blackbody
High temperature extended area blackbody
High-temperature cavity blackbody
A Low-temperature blackbody is a type of black body radiation that has the range of -40° C to 175° C, typically between 233 K and 448 K. A perfect fit for the temperature range mentioned in the question, "a few hundred Kelvin". Therefore, it's the kind of blackbody temperature that the object would emit.
<h3>I think it B The group(s) that gets the special treatment.</h3><h3 /><h3>I hope this is correct.</h3><h3 /><h3 /><h3 />
<h2>
Answer:5
,133.6
,51.18
</h2>
Explanation:
Let 
,
be the horizontal and vertical components of velocity.
Question a:
Horizontal component of velocity is the ratio of range and time of flight.
So,horizontal component of velocity is 
So,
Question b:
Time of flight=
So,
Maximum height is given by 
So,maximum height is 
Question c:
The vertical velocity is already calculated in Question b.
